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galben [10]
4 years ago
12

Secθ =__________________ 1/sinθ +-√cos^2 +1 +-√tan^2 +1

Mathematics
2 answers:
Zielflug [23.3K]4 years ago
6 0

Answer:

The answer is last option

As we know 1 + tan^2 = sec^2

denis-greek [22]4 years ago
5 0

Answer:

secФ = ±\sqrt{1+tan^{2} }

Step-by-step explanation:

We can use the identity sec²Ф = 1 + tan²Ф to solve for secФ

  • First we need to take the square root of both sides to get: \sqrt{sec^{2} } =\sqrt{1+tan^{2} } which then simplifies to
  • secФ = ±\sqrt{1+tan^{2} }
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A phone manufacturer wants to compete in the touch screen phone market. Management understands that the leading product has a le
CaHeK987 [17]

Answer:

Step-by-step explanation:

Hello!

To compete in the touch screen phone market a manufacturer aims to release a new touch screen with a battery life said to last more than two hours longer than the leading product which is the desired feature in phones.

To test this claim two samples were taken:

Sample 1

X: battery lifespan of a unit of the new product (min)

n= 93 units of the new product

mean battery life X[bar]= 8:53hs= 533min

S= 84 min

Sample 2

X: battery lifespan of a unit of the leading product (min)

n= 102 units of the leading product

mean battery life X[bar]= 5:40 hs = 340min

S= 93 min

The population variances of both variances are unknown and distinct.

To test if the average battery life of the new product is greater than the average battery life of the leading product by 2 hs (or 120 min) the parameters of interest will be the two population means and we will test their difference, the hypotheses are:

H₀: μ₁ - μ₂ ≤ 120

H₁:  μ₁ - μ₂ > 120

Considering that there is not enough information about the distribution of both variables, but both samples are big enough, we can apply the central limit theorem and approximate the distribution of both sample means to normal, this way we can use the standard normal:

Z= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{\sqrt{\frac{S_1^2}{n_1} +\frac{S_2^2}{n_2}  } }

Z≈N(0;1)

Z= \frac{(533-340)-120}{\sqrt{\frac{84^2}{56} +\frac{93^2}{102}  } }= 5.028

I hope this helps!

3 0
4 years ago
someone help on the "how did basil know" part before i sue and quit school. i just wanna sleep it's 12 am.
PtichkaEL [24]
Well, the last digit in the product will only come from the last digits of the numbers that you're multiplying together. So for 0.303 & 4.48, that last digits are 3 & 8 so that last digit in the product would come from
3 \times 8 = 24
So 4. There are only two options that end in 4, 1.35744 & 0.13574. You can by the magnitude of the numbers that it isn't as small as 0.13574 so the answer must be 1.35744.
4 0
4 years ago
How do you graph x-y-3=0
Neko [114]

Answer:

see explanation

Step-by-step explanation:

To graph the line, we require 2 points

Find the intercepts, that is where the graph crosses the x and y axes

To find the x- intercept let y = 0 in the equation and solve for x

x - 3 = 0 ( add 3 to both sides )

x = 3 ⇒ (3, 0 ) ← x- intercept

To find the y- intercept let x = 0 in the equation and solve for y

- y - 3 = 0 ( add 3 to both sides )

- y = 3 ( multiply both sides by - 1 )

y = - 3 ⇒ (0, - 3 ) ← y- intercept

Plot the points (3, 0) and (0, - 3) and draw a straight line through them

4 0
3 years ago
The following table gives the science scores and times spent studying for 10 students:
AveGali [126]
There appears to be a positive correlation between the number of hour spent studydng and the score on the test.

When identifying the independent and dependent quantities, we think about what would cause the other to change.  The score on the test would not cause the number of hours spent studying to change; rather, the number of hours spent studying would cause the score to change.  This means that the number of hours studying would be the independent quantity and the score would be the dependent quantity.

Plotting the graph with the time studying on the x-axis (independent) and the score on the y-axis (dependent) gives you the graph shown.  You can see in the image that there seems to be a positive correlation; the data seem to generally be heading upward.

8 0
3 years ago
Write the equation of a line in slope intercept form that is parallel to the line y= 1/3x + 5 and passes through (-9, 5)
vladimir2022 [97]
Find the slope of line 1
The equation of line 1 is y = (1/3)x + 5
m = 1/3

Find the slope of line 2
Line 2 is parallel to line 1. Parallel lines have the same number of slope. So the slope of line 2 is 1/3

Find the slope-intercept form of equation, with m = 1/3 and (-9,5)
General formula
y - y₁ = m(x - x₁)

Input the number to the formula
y - y₁ = m(x - x₁)
y - 5 = 1/3(x - (-9))
y - 5 = 1/3 (x + 9)
y - 5 = (1/3)x + 3
y = (1/3)x + 3 + 5
y = (1/3)x + 8

The equation is y = (1/3)x + 8
7 0
4 years ago
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