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Firlakuza [10]
3 years ago
12

I need 13-18 PLEASE i need it

Mathematics
1 answer:
krok68 [10]3 years ago
3 0
The 13th problem is 1/3
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The graph of the equation x + 3y = 6 intersects at the y axis at the point whose coordinates are
svp [43]

Answer:

4. (6,0)

Step-by-step explanation:

Plug the points into the equation.

6+3(0)=6

6+0=6

6=6

5 0
3 years ago
Can you help me solve. My teacher got those answers but I don’t know how.
valina [46]

Answer:

Your teacher is correct.

Step-by-step explanation:

Common knowledge about coordinates:

The first number in a coordinate is the "x coordinate".

The second number is the "Y coordinate".

The X axis is the horizontal line.

The Y axis is the vertical line.

The origin is the middle of the two axis's.

For A, the x coordinate is -4. You go right on the horizontal line because it is a negative number. The y coordinate is 4, so you go up from -4 to 4 because it is a positive number. there, you'll get your coordinate (-4 , 4).

For B, because the x coordinate is 0, you don't move at all, and you stay on the x origin. The y coordinate is 6, so you go up from the origin to 6. There, you'll have (0, 6).

C is pretty self explanatory if you understand the concept.

3 0
3 years ago
Write a inequality for the sentence then solve the inequality
Digiron [165]
It would be letter. b....
6 0
3 years ago
Read 2 more answers
Given: ΔPSQ, PS = SQ
horrorfan [7]
<h2>Answer:</h2>

To solve this problem we will use Heron's formula:

A=\sqrt{s(s-a)(s-b)(s-c)}

Where a, \ b \ and \ c are the side lengths of the triangle and s is the semiperimeter (half the perimeter of the triangle). We know that:

Perimeter \ P=\triangle PSQ=PS+PQ+SQ: \\ \\ \triangle PSQ=P=50 \\ \\ Semiperimeter \ s: \\ \\ s=\frac{P}{2}=25

Also:

(I) \ PS=SQ \\ \\ (II) \ SQ-PQ = 1 \\ \\ (III) \ PS+PQ+SQ=50 \\ \\ \\ (I) \ into \ (III): \\ \\ SQ+PQ+SQ=50 \\ \\ \therefore (IV) \ 2SQ+PQ=50 \\ \\ From \ (II): \\ \\ PQ=SQ-1 \\ \\ (II) \ into \ (IV): \\ \\ 2SQ+(SQ-1)=50 \\ 3SQ-1=50 \\ 3SQ=51 \\ \\ \boxed{SQ=17} \\ \\ \boxed{PS=17} \\ \\ PQ=SQ-1=17-1 \therefore \boxed{PQ=16}

Finally:

A=\sqrt{s(s-a)(s-b)(s-c)} \\ \\ A=\sqrt{s(s-PS)(s-SQ)(s-PQ)} \\ \\ A=\sqrt{s(s-17)(s-17)(s-16)} \\ \\ A=\sqrt{25(25-17)(25-17)(25-16)} \\ \\ \boxed{A=120}

7 0
3 years ago
What is an "outlier" and how does it effect data like: mean, median and mode
laiz [17]
An outlier affects mean the most
7 0
3 years ago
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