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Ad libitum [116K]

2 years ago

14

For flvs math 7th grade, there is and end of course segment 2 review video, and there is a phrase in it that we need to tell the

teacher does anyone know it?

1 answer:

alexandr402 [8]2 years ago

3 0

Answer:

whos ur math teacher

Step-by-step explanation:

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Prove that angles opposite to equal sides of an isosceles triangle are equal.

ZanzabumX [31]

Answer:

Step-by-step explanation:

Take a triangle ABC, in which AB=AC.

Construct AP bisector of angle A meeting BC at P.

In ∆ABP and ∆ACP

AP=AP[common]

AB=AC[given]

angle BAP=angle CAP[by construction]

Therefore, ∆ABP congurent ∆ACP[S.A.S]

This implies, angle ABP=angleACP[C.P.C.T]

8 0

3 years ago

Is b+b+b+c+c+c is a equivalent expression?<br> A. True <br> B. False

Rama09 [41]

Answer:

A. True

Step-by-step explanation:

......................................................................................

5 0

3 years ago

F(x)=3(x+5)+4/x, what is f(a+2)

likoan [24]

the answer would be= -2fx+3x^2+15+a/fx

8 0

2 years ago

Pls help ASAP !! I’m struggling so hard in math class pls help I need it .

Mama L [17]

Answer:

b = 27 degrees

Step-by-step explanation:

90 - 63 = 27

8 0

3 years ago

Read 2 more answers

Identify the zeros of the function f(x) = 4x2 − 8x − 1 using the Quadratic Formula. HELP ASAP!!

forsale [732]

$1+\dfrac{\sqrt{5}}{2},1-\dfrac{\sqrt{5}}{2}$

Step-by-step explanation:

The given equation is $4x^{2}-8x-1$

Let $a$ be the coefficient of $x^{2}$

Let $b$ be the coefficient of $x$

Let $c$ be the constant.

Then the roots α,β for the equation $ax^{2}+bx+c$ are $\dfrac{-b+\sqrt{b^{2}-4ac} }{2a},\dfrac{-b-\sqrt{b^{2}-4ac} }{2a}$

So,α= $\frac{-b+\sqrt{b^{2}-4ac} }{2a}=\frac{8+\sqrt{64+16} }{8}=\frac{8+4\sqrt{5}}{8}=1+\frac{\sqrt{5}}{2}$

β= $\frac{-b-\sqrt{b^{2}-4ac} }{2a}=\frac{8-\sqrt{64+16} }{8}=\frac{8-4\sqrt{5}}{8}=1-\frac{\sqrt{5}}{2}$ .

So the roots are $1+\frac{\sqrt{5}}{2},1+\frac{\sqrt{5}}{2}$

5 0

3 years ago