Answer:
The figure is a straight line.
The figure lies in the first and the third quadrants.
Step-by-step explanation:
Take five ordered pairs as 
Here, the first and second coordinates are equal.
Now, plot these points and connect them.
From the graph, it can be observed that the figure is a straight line.
Also, the figure lies in the first and the third quadrants.
Answer: E(X) = 30; Var[X] = 180
Step-by-step explanation: This is a <u>Bernoulli</u> <u>Experiment</u>, i.e., the experiment is repeated a fixed number of times, the trials are independents, the only two outcomes are "success" or "failure" and the probability of success remains the same, So, to calculate <em><u>Expected</u></em> <em><u>Value</u></em>, which is the mean, in these conditions:

r is number of times it is repeated
p is probability it happens
Solving:

E(X) = 30
<u>Variance</u> is given by:
![Var[X]=\frac{r(1-p)}{p^{2}}](https://tex.z-dn.net/?f=Var%5BX%5D%3D%5Cfrac%7Br%281-p%29%7D%7Bp%5E%7B2%7D%7D)
![Var[X]=\frac{5(1-1/6)}{(1/6)^{2}}](https://tex.z-dn.net/?f=Var%5BX%5D%3D%5Cfrac%7B5%281-1%2F6%29%7D%7B%281%2F6%29%5E%7B2%7D%7D)
![Var[X]=5.\frac{5}{6}.6^{2}](https://tex.z-dn.net/?f=Var%5BX%5D%3D5.%5Cfrac%7B5%7D%7B6%7D.6%5E%7B2%7D)
Var[X] = 180
Expected Value and Variance of the number of times one must throw a die until 1 happens 5 times are 30 and 180, respectively.
Y = 6, z = 2
~Hope this helped!~
(The first page is the beginning of the equation, and the next page is the ending)
The exponent is 6, since 7^6 is the same as (see picture).
B is the answer.
x (the variable for number of hours worked) must be connected the number indicating the hourly rate, which is 56.
375 must be added at some point in the equation due to it being an indicated signing bonus (it has to be added).