3 years ago

Write the words as decimals

Mathematics

2 answers:

dezoksy [38]3 years ago

8 0

8) 2,164.8

9) 304.07

10) $421.37

cestrela7 [59]3 years ago

5 0

8. 2,164.8

9. 304.07

10. $421.37

I hope this helps!!!

You might be interested in

HELP ME FAST PLEASE I NEED THIS VERY SOON!!! you’d be a lifesaver omg

madam [21]

712 is the answer of this question

6 0

2 years ago

Read 2 more answers

Samuel used 1/5 of an ounce of butter to make 1/15 of a pound of jelly. How many ounces of butter are needed to make a pound of

Zanzabum

1/5 x 15= 3 ounces of butter needed

8 0

3 years ago

If X squared equals 16 then X equals 4

AfilCa [17]

That would be correct because if x times x =16 than that means that the square root of 16 is 4

6 0

3 years ago

The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of

ser-zykov [4K]

Answer:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$ , for $r_{1} = 0$

Step-by-step explanation:

The general form of quintic-order polynomial is:

$p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f$

According to the statement of the problem, the polynomial has the following roots:

$p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)$

Then, some algebraic handling is done to expand the polynomial:

$p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)$

$p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x$

If $r_{1} = 0$ , then:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$

5 0

2 years ago

7.3033 to the nearest foot

pychu [463]

Answer:

7 feet

Step-by-step explanation:

If it is under .5 keep the whole number the same, if it is .5 or more round up. This is .3 so it is 7.

7 0

3 years ago

Read 2 more answers