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jenyasd209 [6]
3 years ago
11

peg and larry purchased "no contract" cell phones. Peg's phone cost $25 plus $0.25 per minute. Larry's phone cost $35 plus $0.20

per minute. After haw many minutes of use will Peg's phone cost more then Larry's phone?
Mathematics
2 answers:
sukhopar [10]3 years ago
4 0
Do you have a graphing calculator?
valina [46]3 years ago
4 0

Solution:

Peg's phone cost $25 plus $0.25 per minute.

Larry's phone cost $35 plus $0.20 per minute.

Let Peg's phone cost more then Larry's phone after t minutes.

Then we can write

25+0.25t=35+0.20t\\
\\
35-25=0.25t-0.20t\\
\\
10=0.05t\\
\\
t=200

Hence Let Peg's phone cost more then Larry's phone after 200 minutes.

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Metal A has a density of 12.7 g/cm3.
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Using the given information, the density of metal B is 8.58 g/cm³

<h3>Calculating density </h3>

From the question, we are to determine the density of metal B

From the given information,

55 g of metal A is combined with metal B to create an alloy with mass 90 g

∴ Mass of metal B in the alloy = 90 g - 55 g = 35 g

Now, we will determine the volume of metal A in the alloy

Using the formula,

Density = Mass / Volume

∴ Volume = Mass / Density

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Volume of metal A in the alloy = 4.33 cm³

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Density of metal B = 35 / 4.08

Density of metal B = 8.58 g/cm³

Hence, the density of metal B is 8.58 g/cm³.

Learn more on Calculating density here: brainly.com/question/13986137

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