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Agata [3.3K]
3 years ago
13

Part A and B Please 10 points

Mathematics
2 answers:
Flura [38]3 years ago
5 0
For part a I would say you can’t use that translation to change it back to the original triangle. I tried the rule out for myself


My coordinate was 3, 6 and applied the -7 -6 rule and got -4,0.

Then I used the rule that they have to translate it back which was -6 -7 and there’s no way it can be translated back to 3, 6

So the answer is no the rule can’t be used to translate it back


Can you mark branliest
denis-greek [22]3 years ago
4 0
Same thing the person above said
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One day, a sprinter runs the 100 m dash 24 times, for a total distance of 24 00 m. how many kilometers did the sprinter run?
tigry1 [53]

The total distance that was covered by the sprinter in Kilometers is:

  • 2.4 Km

<h3>How much is the total distance covered?</h3>

To obtain the total distance covered by the sprinter, we need to first realize that 1 Km is equal to 1000 meters. That said, the question above requires us to change 2400 meters to kilometers.

Thus we will have:

2400 Meters * 1 km / 1000 meters

= 2.4 km

So, the total distance covered by the sprinter in kilometers is 2.4

Learn more about meter conversions here:

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4 0
1 year ago
Factor the polynomial. 54c3d4 + 9c4d2 A. 9c3d2(d2 + 6c) B. 9c3d2(6d2 + c) C. 9c4d2(d2 + 6) D. 9c4d2(6d2 + 1)
11Alexandr11 [23.1K]
Answer is = 9c^3 d^2 (6d^2 + c)
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3 years ago
y = c1 cos(5x) + c2 sin(5x) is a two-parameter family of solutions of the second-order DE y'' + 25y = 0. If possible, find a sol
TEA [102]

Answer:

y = 2cos5x-9/5sin5x

Step-by-step explanation:

Given the solution to the differential equation y'' + 25y = 0 to be

y = c1 cos(5x) + c2 sin(5x). In order to find the solution to the differential equation given the boundary conditions y(0) = 1, y'(π) = 9, we need to first get the constant c1 and c2 and substitute the values back into the original solution.

According to the boundary condition y(0) = 2, it means when x = 0, y = 2

On substituting;

2 = c1cos(5(0)) + c2sin(5(0))

2 = c1cos0+c2sin0

2 = c1 + 0

c1 = 2

Substituting the other boundary condition y'(π) = 9, to do that we need to first get the first differential of y(x) i.e y'(x). Given

y(x) = c1cos5x + c2sin5x

y'(x) = -5c1sin5x + 5c2cos5x

If y'(π) = 9, this means when x = π, y'(x) = 9

On substituting;

9 = -5c1sin5π + 5c2cos5π

9 = -5c1(0) + 5c2(-1)

9 = 0-5c2

-5c2 = 9

c2 = -9/5

Substituting c1 = 2 and c2 = -9/5 into the solution to the general differential equation

y = c1 cos(5x) + c2 sin(5x) will give

y = 2cos5x-9/5sin5x

The final expression gives the required solution to the differential equation.

3 0
3 years ago
Passes through (1,4) and is parallel to the line y=2x-3
Novay_Z [31]

Answer:

y = 2x + 2

Step-by-step explanation:

Slope = 2

y-intercept: 4 - (2)(1) = 2

3 0
2 years ago
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