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Andrei [34K]
3 years ago
6

I REALLY NEED THIS ANSWERED STRAIGHT AWAY PLEASE!!!!!! A juice company decides to test five different brands of juice. The diffe

rent brands have been labeled A, B, C, D, AND E. The company decides to compare each brand with the other brands by pairing together different brands. How many different pairs will result by selecting two different brands at a time?
A.11
B.15
C.120
D.10
Mathematics
1 answer:
liberstina [14]3 years ago
6 0
10 different pairs. Since there are 5 different brands you simply add 4+3+2+1 to get 10.
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Yoonie is a personnel manager in a large corporation. Each month she must review 16 of the employees. From past experience, she
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Answer:

P(3.25 < \bar X < 4.25)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\sigma_{\bar X}}

And using the z score we have:

P(\frac{3.5-4}{0.3}< Z< \frac{4.25-4}{0.3}) = P(-1.667< Z< 0.833)

And we can use the normal standard distribution table or excel in order to find the probabilities and we got:

P(-1.667< Z< 0.833)= P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the time it takes her to complete one review, and for this case we know the distribution for X is given by:

X \sim N(4,1.2)  

Where \mu=4 and \sigma=1.2

And we select a sample size of n =16. Since the dsitribution for X is normal then the distribution for the sample mean \bar X is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\sigma_{\bar X}= \frac{1.2}{\sqrt{16}}= 0.3

For this case we want to find this probability:

P(3.25 < \bar X < 4.25)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\sigma_{\bar X}}

And using the z score we have:

P(\frac{3.5-4}{0.3}< Z< \frac{4.25-4}{0.3}) = P(-1.667< Z< 0.833)

And we can use the normal standard distribution table or excel in order to find the probabilities and we got:

P(-1.667< Z< 0.833)= P(Z

The graph illustrating the problem is on the figure attached.

4 0
3 years ago
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