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2 years ago

In the problem 10 take away 4 equals 6 what is the correct term for the number 4

Mathematics

2 answers:

Aleksandr [31]2 years ago

7 0

Subtrahend is the correct way to say it

crimeas [40]2 years ago

5 0

10 would be called the Minuend.
4 would be called the Subtrahend.
4 would be the Difference.

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What is 2/3 divided by 4 in the Simplest form?

dsp73

Answer:

2/3 divided by 4 = .16

4 0

2 years ago

Read 2 more answers

Solve they system by addition 7x-2y=3 4x+5y=3.25

noname [10]

Answer: x = 2/7y + 3/7 and

x= -5/4y + 0.8125

Step-by-step explanation: Let's solve for x.

7x−2y=3

Step 1: Add 2y to both sides.

7x − 2y + 2y= 3 + 2y

7x = 2y + 3

Step 2: Divide both sides by 7.

7x/7 = 2y+3/7 this is for the second answer Step 1: Add -5y to both sides.

4x+5y+−5y=3.25+−5y

4x=−5y+3.25

Step 2: Divide both sides by

4/4 x 4 = −5y + 3.25/4

4 0

2 years ago

A library charges a late return fee of 3.50 plus $0.15 per day that a book is returned late write a equation to find the total l

joja [24]

The equation would be:

3.50 + 0.15x

x represents each 'late day'

7 0

2 years ago

Customers arrive at a movie theater at the advertised movie time only to find that they have to sit through several previews and

Naddika [18.5K]

Answer:

Using a 90% confidence level

A. A sample size of 68 should be used.

B. A sample size of 98 should be used.

Step-by-step explanation:

I think there was a small typing mistake and the confidence level was left out. I will use a 90% confidence level.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

A. If we want to estimate the population mean time for previews at movie theaters with a margin of error of 72 seconds, what sample size should be used?

We have the standard deviation in minutes, so the margin of error should be in minutes.

72 seconds is 72/60 = 1.2 minutes.

So we need a sample size of n, and n is found when M = 1.2. We have that $\sigma = 6$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$1.2 = 1.645*\frac{6}{\sqrt{n}}$

$1.2\sqrt{n} = 6*1.645$

$\sqrt{n} = \frac{6*1.645}{1.2}$

$(\sqrt{n})^{2} = (\frac{6*1.645}{1.2})^{2}$

$n = 67.65$

Rounding up.

A sample size of 68 should be used.

B. If we want to estimate the population mean time for previews at movie theaters with a margin of error of 1 minute, what sample size should be used?

Same logic as above, just use M = 1.

$M = z*\frac{\sigma}{\sqrt{n}}$

$1 = 1.645*\frac{6}{\sqrt{n}}$

$\sqrt{n} = 6*1.645$

$(\sqrt{n})^{2} = (6*1.645)^2$

$n = 97.42$

Rounding up

A sample size of 98 should be used.

3 0

2 years ago

Elizabeth wrote 3.3 - 0.21= 1.2 Is her answer reasonable? Explain why or why not. Choose the correct answer below and fill in t

scoray [572]

Answer:

<h3>The estimate would be 3-0= nothing, so her answer is not reasonable.</h3>

Step-by-step explanation:

Given the expression written by Elizabeth as 3.3 - 0.21= 1.2, to check if Elizabeth expression is reasonable or not, we need to check if her answer is close to or equal to the answer of the diiferebce between 3.3 - 0.21.

Converting 3.3 and 0.21 to fraction

3.3 = 33/10

0.21 = 21/100

Taking the difference of both fractions

$= \dfrac{33}{10} -\dfrac{21}{100} \\\\= \dfrac{330-21}{100} \\\\= \dfrac{309}{100} \\\\= 3.09\\$

Hence 3.3 - 0.21 = 3.09 ≈ 3.0 (to nearest whole number). Comparing Elizabeth answer which is 1.2 to the answer f=gotten, it can be seen that her answer is far from the right answer with a difference of about 1.8 (3.0-1.2). <u>This large difference makes Elizabeth answer unreasonable.</u>

7 0

3 years ago