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I am Lyosha [343]
3 years ago
12

a strip of paper is 9/10 of an inch long. you need to cut the paper into 3/12 inch pieces. how many pieces will you be able to c

ut?
Mathematics
1 answer:
e-lub [12.9K]3 years ago
5 0
We have to divide 9/10 by 3/12.

if we divide by a fraction, we can instead multiply by it's inverse:

\frac{9}{12}/ \frac{3}{12}  = \frac{9}{12} * \frac{12}{3}

so now we count:

\frac{9}{12} * \frac{12}{3} =\frac{9}{1} * \frac{1}{3}=3

so we can cut exactly 3 pieces!



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Kenya has 2 hours to make a 104 mile trip. What rate must she average to make the trip in 2 hours? A) 50 mph B) 51 mph C) 52 mph
sattari [20]
C. 52 mph.
104\2 = 52
8 0
3 years ago
How many 2/3- cup servings are in 6 cups of yogurt
Citrus2011 [14]
6 / (2/3)
= 6 * 3/2
= 18/2
= 9

answer

there are 9 (2/3 cup) servings in 6 cups of yogurt
8 0
3 years ago
Read 2 more answers
(7,5), (r,9) m=6<br><br> What is r?
Igoryamba

Answer:

The answer is that r = 7/6

Step-by-step explanation:

Given point: (7, 5)

Given slope: m = 6

Use the point slope form of the equation:

y - y1 = m(x - x1)

y - 5 = 6(x - 7)

y - 5 = 6x - 7

y = 6x + 2

Now, find r for the point (r, 9) by substitution:

9 = 6x + 2

6x + 2 = 9

6x = 7

x = 7/6

Proof:

y = 6x + 2

f(x) = 6x + 2

f(7/6) = 6(7/6) + 2

= 42/6 + 2

= 7 + 2 = 9, giving (7/6, 9). r = 7/6

Hope this helps! Have a great day!

4 0
3 years ago
A line in the xy-plane that passes through the coordinate points (3, -6) and (–7, –4) will never intersecta line that is represe
anyanavicka [17]

Answer:

option A

Step-by-step explanation:

given coordinate (3, -6) and (–7, –4)

to find the equation of line

slope of the line passing through both the point will be

               m = \dfrac{y_2-y_1}{x_2-x_1}

               m = \dfrac{-4+6}{-7-3}

               m = -\dfrac{2}{10}

equation of line

( y - y₁ ) = m ( x - x₁ )

y + 6= -\dfrac{2}{10}(x - 3)

x + 5 y = -27

line which will not intersect will be parallel to it so option A has same slope as our line equation i.e. -1/5

hence, correct answer is option A

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \
Kisachek [45]

Answer:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2

Step-by-step explanation:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} = \ ?

We can use Part I of the Fundamental Theorem of Calculus:

  • \displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

  • \displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

  • \displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

  • \displaystyle\int\limits^b_a \text{f(t) dt}\  = -\int\limits^a_b \text{f(t) dt}

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

  • \displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx}  \int\limits^{x^2}_0 t^2+1 \text{ dt}  

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

  • \displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]
  • where u represents any function other than a variable

For the first term, replace \text{t} with 2x, and apply the chain rule to the function. Do the same for the second term; replace

  • \displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)  

Simplify the expression by distributing 2 and 2x inside their respective parentheses.

  • [-(8x^2 +2)] + (2x^5 + 2x)
  • -8x^2 -2 + 2x^5 + 2x

Rearrange the terms to be in order from the highest degree to the lowest degree.

  • \displaystyle2x^5-8x^2+2x-2

This is the derivative of the given integral, and thus the solution to the problem.

6 0
3 years ago
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