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lara [203]
3 years ago
5

Three consecutive even integers such that 12 less than three times the largest is equal to 96 more than the sum of the first and

second. what is the first even integer?
Mathematics
1 answer:
Marat540 [252]3 years ago
8 0
<span>Let n, n+2, and n+4 represent the three consecutive even integers.

</span>
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Solve for B.<br><br> A=3B+7C
Archy [21]

Hey there!!

Given:

... A=3B+7C

Subtracting 7C on both sides:

... A-7C=3B

Dividing by B on both sides:

... (A-7C)/3=B

<em>Hope my answer helps!</em>

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3 years ago
If 23% of "A" is 46 , then find "A"
neonofarm [45]

Step-by-step explanation:

23percent *A=46

23/100*A=46

A=46*100/23

A=200

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3 years ago
Michael works mowing lawns and babysitting. He earns $8.90 an hour for mowing and $7.20 an hour for babysitting. How
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The answer is $37.70
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Let: f(x)=x+1 and g(x)=x^2-2 <br><br> find: g(x) - f(x)
weeeeeb [17]

Answer:

x^2-x-3

Step-by-step explanation:

x^2-2-x-1

x^2-x-3

3 0
3 years ago
What’s the answer to this?
Hoochie [10]

Answer:

The missing term is:

a_2=14

Step-by-step explanation:

Considering the geometric sequence

2,\:?,\:98,\:...

Here,

a_1=2

a_3=98

a_2=?

The general term of a geometric sequence is given by the formula:

a_n=a_1\cdot \:r^{n-1}

where a_1 is the initial term and r the common ratio.

as

a_3=a_1\cdot \:r^{3-1}

98=2\cdot \:r^{3-1}         ∵ a_1=2

\mathrm{Switch\:sides}

2r^{3-1}=98

\mathrm{Divide\:both\:sides\:by\:}2

\frac{2r^{3-1}}{2}=\frac{98}{2}

r^{3-1}=49

r^2=49

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

r=\sqrt{49},\:r=-\sqrt{49}

r=7,\:r=-7

Taking positive value of r = 7

a_2=a_1\cdot \:r^{n-1}

putting r = 7

a_2=2\cdot \:7^{2-1}

a_2=2\cdot \:7

a_2=14

So, the sequence becomes  2,\:14,\:98,\:...

Therefore, the missing term is:

a_2=14

4 0
3 years ago
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