Question

The roads that connect three buildings form a right triangle. Use the image to find the distance between the parking garage and the theater.

Answer 1

C=100yd, a=60yd, find b
(60yd)^2+b^2=(100yd)^2
3600 yd^2+ b^2 = 10000 yd^2
b^2 = 10000-3600 yd^2
b = sqrt(6400 yd^2)
b=80 yd

Answer 2

Answer:

$80\ yd$

Step-by-step explanation:

Let

x------> the distance between the parking garage and the theater

we know that

In a right triangle

Applying the Pythagoras Theorem

$c^{2} =a^{2}+b^{2}$

where

c is the hypotenuse

a,b are the legs of the triangle

In this problem we have

$c=100\ yd, a=60\ yd, b=x\ yd$

substitute and solve for x

$100^{2} =60^{2}+x^{2}$

$x^{2}=100^{2}-60^{2}$

$x^{2}=6,400$

$x=80\ yd$