Answer:
Part 1) ![(10x+15y)^{2}=(6x+9y)^{2}+(8x+12y)^{2}](https://tex.z-dn.net/?f=%2810x%2B15y%29%5E%7B2%7D%3D%286x%2B9y%29%5E%7B2%7D%2B%288x%2B12y%29%5E%7B2%7D)
Part 2) The answer in the procedure
Step-by-step explanation:
Part 1)
we know that
Applying the Pythagoras Theorem
![c^{2}=a^{2}+b^{2}](https://tex.z-dn.net/?f=c%5E%7B2%7D%3Da%5E%7B2%7D%2Bb%5E%7B2%7D)
we have
![c=(10x+15y)](https://tex.z-dn.net/?f=c%3D%2810x%2B15y%29)
![a=(6x+9y)](https://tex.z-dn.net/?f=a%3D%286x%2B9y%29)
![b=(8x+12y)](https://tex.z-dn.net/?f=b%3D%288x%2B12y%29)
substitute the values
![(10x+15y)^{2}=(6x+9y)^{2}+(8x+12y)^{2}](https://tex.z-dn.net/?f=%2810x%2B15y%29%5E%7B2%7D%3D%286x%2B9y%29%5E%7B2%7D%2B%288x%2B12y%29%5E%7B2%7D)
Part 2) Transform each side of the equation to determine if it is an identity
![(10x+15y)^{2}=(6x+9y)^{2}+(8x+12y)^{2}\\ \\100x^{2}+150xy+225y^{2}=36x^{2}+54xy+81y^{2}+64x^{2}+96xy+144y^{2}\\ \\100x^{2}+150xy+225y^{2}=100x^{2}+150xy+225y^{2}](https://tex.z-dn.net/?f=%2810x%2B15y%29%5E%7B2%7D%3D%286x%2B9y%29%5E%7B2%7D%2B%288x%2B12y%29%5E%7B2%7D%5C%5C%20%5C%5C100x%5E%7B2%7D%2B150xy%2B225y%5E%7B2%7D%3D36x%5E%7B2%7D%2B54xy%2B81y%5E%7B2%7D%2B64x%5E%7B2%7D%2B96xy%2B144y%5E%7B2%7D%5C%5C%20%5C%5C100x%5E%7B2%7D%2B150xy%2B225y%5E%7B2%7D%3D100x%5E%7B2%7D%2B150xy%2B225y%5E%7B2%7D)
The left side is equal to the right side
therefore
Is an identity
Answer:
-Do not touch the contacts or interconnects or pads on ( RAM/DIMM's, GPU / Graphic's Card's, CPU / Processor )
-Not being concerned or cautious about ESD
-Do not over torque / over tighten screws.
-Not giving yourself enough room to build
-Not using a magnetic tray when building
The answer is: D) 115
The explanation is shown below:
1. You have that the frequency with which a cricket chirps varies directly with the temperature, which you can express it as following:
![y=kx](https://tex.z-dn.net/?f=y%3Dkx)
Where
is the frequency with which a cricket chirps,
is the temperature and
is the constant of proportionality.
2. If the cricket chirps 100 times per minute in 80° weather, you can calculate
as below:
![k=\frac{100}{80}=1.25](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B100%7D%7B80%7D%3D1.25)
3. Therefore, the frequency in 92° weather is:
![y=1.25x\\y=(1.25)(92)\\y=115](https://tex.z-dn.net/?f=y%3D1.25x%5C%5Cy%3D%281.25%29%2892%29%5C%5Cy%3D115)
Answer:
The answer is 6cm
Step-by-step explanation:
2cm(the one on top) and 4cm are directly opposite the unknown side which is the same when being cut horizontally so therefore the unknown side is equal to 2cm+4cm which is = 6cm