Answer:
7
Step-by-step explanation:
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer:
Quadrant 1
Step-by-step explanation:
The co-ordinates given match up exactly to co-ordinate 1 due to all the numbers given being positive.
There are 4 quadrants. Quadrant 1, 2, 3, and 4.
Answer:
to know the summation of angles: (n-2)*180
here (n) represent numbers of sides
12)we have 5 sides (n=5)
(5-2)*180=540
x=540-(105+135+92+87)=121
13)we have 8 sides (n=8)
(8-2)*180=1080
x=1080-(116+158+141+124+136+132+129)=144
I hope it will help
1/12 I think I’m sorry if it isn’t