Answer:

Step-by-step explanation:
Given:

To determine the equation of the line, we will use point slope form.
<u>Formula of point slope form:</u>
Where "x₁" and "y₁" are the coordinates of the point and "m" is the slope.
Substitute the coordinates and the slope:

Simplify the R.H.S:

Add 1 both sides:

Simplify the equation:


<u>Graphing the line on a coordinate plane:</u>
In this case, we are already given a point (3, 1). We can simply plot the y-intercept
on the coordinate plane. Then, we can draw a straight line through both points. It is suggested that you use a ruler to do so.
Graph attached**
Hello,
the transformation that applies (x,y) to (-x,-y) is a symmetry by the origin.
Every symmetry transforms a line into a line.
So the new points are also collinear.
I guess so, no wait no it’s not jk lol
Answer:
Step-by-step explanation:
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