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2 years ago

Calculate the taxes based on the following taxable income amounts

Mathematics

1 answer:

Bingel [31]2 years ago

4 0

1.) Taxable income is 22,764.42 (income 90,714 less range which is more than 87,850 but less than 183,250 = 2,864 multiply to its corresponding tax rate of 28% = 801.92 plus its corresponding amount of 21,962.50 = 22,764.42)

2.) Taxable income is 12,140.75

3.) Taxable income is 63,634.18

4.) Taxable income is 44,097.62

5.) Taxable income is 63,691.60

6.) Taxable income is 24,598.98

7.) Taxable income is 59,234.62

8.) Taxable income is 171,662.58

9.) Taxable income is 184,033.22

10.) Taxable income is 183,997.18

11.) Taxable income is 61,067.11

12.) Taxable income is 153,877.82

13.) Taxable income is 241,356.99

14.) Taxable income is <span>274,376.26
</span>
15.) Taxable income is 97,208.05

Note: Use the "from" amount as the basis, so if the income is 10,000 then you'll deduct 8,925 (basis) from 10,000 (since 10,000 is more than 8,925 but less than 36,250)

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Assume that females have pulse rates that are normally distributed with a mean of beats per minute and a standard deviation of b

snow_tiger [21]

Answer:

a) This is the p-value of Z when X = A subtracted by the p-value of Z when X = B.

b) P-value of Z when X = 76 subtracted by the p-value of X = 68.

c) Because the underlying distribution(pulse rates of females) is normal.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Mean $\mu$ , standard deviation $\sigma$ .

standard deviation of beats per minute.

a. If 1 adult female is randomly selected, find the probability that her pulse rate is between A beats per minute and B beats per minute.

This is the p-value of Z when X = A subtracted by the p-value of Z when X = B.

b. If 4 adult females are selected, find the probability that they have pulse rates with a mean between 68 beats per minute and 76 beats per minute.

Sample of 4 means that we have $n = 4, s = \frac{\sigma}{\sqrt{4}} = 0.5\sigma$

The formula for the z-score is:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{X - \mu}{0.5\sigma}$

$Z = 2\frac{X - \mu}{\sigma}$

This probability is the p-value of Z when X = 76 subtracted by the p-value of X = 68.

c. Why can the normal distribution be used in heartbeat even the sample side does not exceed 30?

Because the underlying distribution(pulse rates of females) is normal.

3 0

2 years ago

What is x/y ? Help pls

algol [13]

Answer:

ok I really suck at math, but I think you may have to multiply the x/y to get the whole area of the circle. so maybe itd be 10x25. I'm sorry if this isnt correct

8 0

2 years ago

At a college the scores on the chemistry final exam are approximately normally distributed, with a mean of 75 and a standard dev

AysviL [449]

Answer:

b) Chemistry

Step-by-step explanation:

To compare both scored we need to standardize the scores using the following equation:

$\frac{x-m}{s}$

Where x is the score, m is the mean and s is the standard deviation. So, 82 on chemistry is equivalent to:

$\frac{82-75}{15}=0.4667$

Because the mean of the scores on the chemistry final exam is equal to 75 and the standard deviation is 15

At the same way, 80 on Calculus is equivalent to:

$\frac{80-83}{13} =-0.2308$

Because the mean of the scores on the calculus final exam is equal to 83 and the standard deviation is 13

Now, we can compare the values. So, taking into account that -0.2308 is lower than 0.4667, we can said that the student do better in Chemistry.

5 0

2 years ago

James said that he would need 25 red beads to make

o-na [289]

Answer:Elena uses 12 red beads to make 4 bracelets. How many red beads will Elena need to make 12 bracelets? How many red beads will Elena need to make 20 bracelets? You can make a table showing the number of bracelets that can be made with different numbers of red beads. The pairs of numbers in each column show the ratio ofred beads to bracelets. Notice the ratios are all equivalent.

Number of Red Beads 3 6 12 24 36 48 60 72 Number of Bracelets 1 2 4 8 12 16 20 24

The table shows Elena will need 36 red beads to make 12 bracelets. Elena will need 60 red beads to make 20 bracelets. James said that he would need 25 red beads to make 75 bracelets. Is he correct? How did he get that answer?

Step-by-step explanation:

5 0

2 years ago

Susie has 8/9 <br> cup of ice cream. How many 1/4<br> cup servings can she make?

trapecia [35]

Answer:8 cup servings. 1/4×8=8/4

Step-by-step explanation:

3 0

2 years ago