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Veronika [31]
4 years ago
14

Divide -3x^3-2x^2-x-2 by x-2

Mathematics
1 answer:
tatuchka [14]4 years ago
4 0
In this case, you must synthetic division. You are given x-2. You need to set that to zero so that you now have x-2=0. You then need to get x by itself. So:
x-2(+2)=0(+2) \\ x=2.
You then need to use that final part as the beginning of your synthetic division.
To continue, you must find the leading coefficients of every degree (remember: your degree is found by your largest exponent) beginning with your highest degree, in this case it is 3, and use the front number of the term. BE SURE TO BE AWARE OF NEGATIVES (indicated by subtraction signs)!!! Then you continue down the equation from x^{3} down tox^{2} then x^{1} then x^{0} (which is just the number without an "x") doing the same thing. So your setup should look similar to as follows:

2 l -3  -2  -1  -2
   l__________

The numbers inside the box should be added down (the first number is added to nothing, so it is added to zero. Then it is multiplied by the outside number (2). Then that multiplied number continues into the next slot within the box which is then added to the number above it, and so the process repeats. So the process should go like this.

2  l -3  -2  -1  -2
    <u>l  </u><u>0              
</u>      -3
2  l -3  -2  -1  -2
<u />    <u>l </u><u> 0  -6         </u>
      -3  -8
2  l -3  -2  -1  -2
    <u>l  </u><u>0  -6 -16    
</u>      -3  -8 -17
2  l -3  -2  -1  -2
    <u>l  </u><u>0  -6 -16 -34
</u>      -3  -8 -17 -36
So now you are left with -3, -8, -17, and -36. This is to be expected. Now, those new numbers are your new leading coefficients. Remember your first degree? It was 3, now, you need to take your leading degree and subtract it by one. That is your new degree. So now, going left to right on the synthetic division chart, you add "x" and your degree descending as you go further to the right. So, your new equation is -3 x^{2} -8 x-17.
There is a problem though, because there is still that -36. This is where that original piece that you divided the equation by comes in handy. You divided everything by x-2, so, you must add your remainder divided by x-2 to the rest of the equation.
So, the final equation is equal to:
-3 x^{2} -8x-17- \frac{36}{x-2}

That is your final answer.
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It can be created 1575 license plated with at least one three-piece palindrome.

Step-by-step explanation:

If a license plates has at least one three-piece palindrome, we have the following cases:

1. The license plate just has a palindrome in the three numbers: The number license plates for this case can be calculated using the rule of multiplication as:

<u>   5              </u>*<u>      5      </u>* <u>      1       </u>* <u>        3         </u>*<u>      3       </u>*<u>      2       </u>=  450

1st Number        2nd        3rd          1st Letter       2nd           3rd

For have a palindrome in the numbers, the first and the 3rd number need to be the same. So, we have 5 digits for the first and the 2nd Number and one digit for the 3rd Number.

On the other hand, if the palindrome is just in the numbers, the 3rd letter need to be different from the 1st. So we have 3 options for the 1st and the 2nd letter and 2 options for the 3rd letter.

At the same way, we can calculated the number of license plates for the other cases:

2. The license plate just has a palindrome in the three letters:

<u>   5              </u>*<u>      5      </u>* <u>      4       </u>* <u>        3         </u>*<u>      3       </u>*<u>      1       </u>=  900

1st Number        2nd        3rd          1st Letter       2nd           3rd

3. The license plate has a palindrome in the three numbers and in the letters:

<u>   5              </u>*<u>      5      </u>* <u>      1       </u>* <u>        3         </u>*<u>      3       </u>*<u>      1       </u>=  225

1st Number        2nd        3rd          1st Letter       2nd           3rd

Then, It can be created 1575 license plates with at least one three-piece palindrome and it is calculated as:

450 + 900 + 225 = 1575

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