Ax+bx−c=0

Step 1: Add c to both sides.

ax+bx−c+c=0+c

ax+bx=c

Step 2: Factor out variable x.

x(a+b)=c

Step 3: Divide both sides by a+b.

x(a+b)a+b=ca+b

x=ca+b

4 0

3 years ago

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Determine whether each set of data represents a linear, an exponential, or a quadratic function. (Desmos)

Cerrena [4.2K]

Answer:

Linear: The first and third one. (0,5) & (1,1)

Exponential: The second one (above). (-2, 1/16)

Quadratic function: The last one (below). (-3,35)

Step-by-step explanation:

4 0

3 years ago

Identify the "inside function" u = f(x) and the "outside function" y = g(u). Then find dy/dx using the Chain Rule.

skad [1K]

DfLet $f(x)=\sec x$ and $g(x)=\sqrt x$ . Then

$y=\sec\sqrt x=\sec(g(x))=f(g(x))=f\circ g(x)$

By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx}$

where $u=g(x)=\sqrt x$ , so that $y=f(g(x))=f(u)=\sec u$ . We have

$\dfrac{\mathrm du}{\mathrm dx}=\dfrac1{2\sqrt x}$
$\dfrac{\mathrm d\sec u}{\mathrm du}=\sec u\tan u$

and so

$\dfrac{\mathrm dy}{\mathrm dx}=\sec u\tan u\dfrac{\mathrm dy}{\mathrm du}=\dfrac{\sec\sqrt x\,\tan\sqrt x}{2\sqrt x}$

5 0

3 years ago

Anyone wanna play cod or 2k hop on rn

Thepotemich [5.8K]

Answer:

Sure

Step-by-step explanation:

6 0

3 years ago

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