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Digiron [165]
3 years ago
5

The ratio of 20 and 5

Mathematics
2 answers:
Travka [436]3 years ago
5 0

<em>ANSWER:</em>

<h2>20:5</h2>

<em>STEP:</em>

Since you said 20 first, and 5 after, the answer is 20:5. Or, you can also write 5:1. Since ratios are fraction. 20/5 is 20:5. Now simplify 20/5. It is 5/1. Therefore, the answer is 20:5.

IrinaK [193]3 years ago
4 0
The ratio of 20 and 5 is 40:10, 60:15, 80:20
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I need help with number 33 thank u!
Rufina [12.5K]

Answer:

C. 2,150

Step-by-step explanation:

We know that out of 120 passengers, 86 were satisfied with the service.

To find the percentage amount of passengers who were satisfied, we can divide 86 by 120 and get 0.716 repeating (about 71.6%).

Then, we can multiply the total number of passengers, 3,000, by that number and get 2,150.

7 0
3 years ago
There are about 16 kilometers in 10 miles. About how many kilometers are in 5 miles
IRISSAK [1]

8 kilometers is the answer

Hope this helps!:)

5 0
3 years ago
A bag contains 4 red balls, 2 green balls, 3 yellow balls, and 5 blue balls. Find each probability for randomly removing balls w
AfilCa [17]

Answer:

\frac{15}{4802}, \frac{15}{9604}, \frac{9}{2401}, \frac{9}{4802}

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: \frac{4}{14}

green: \frac{2}{14}

yellow: \frac{3}{14}

blue: \frac{5}{14}

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = \frac{3}{14} \cdot \frac{4}{14}  \cdot \frac{2}{14}  \cdot \frac{5}{14} =\frac{15}{4802}

Removing 1 blue, 1 green, 1 green, and 1 yellow = \frac{5}{14} \cdot \frac{2}{14}  \cdot \frac{2}{14}  \cdot \frac{3}{14} =\frac{15}{9604}

Removing 1 red, 1 red, 1 yellow, and 1 yellow = \frac{4}{14} \cdot \frac{4}{14}  \cdot \frac{3}{14}  \cdot \frac{3}{14} =\frac{9}{2401}

Removing 1 green, 1 yellow, 1 yellow, and 1 red = \frac{2}{14} \cdot \frac{3}{14}  \cdot \frac{3}{14}  \cdot \frac{4}{14} =\frac{9}{4802}

4 0
2 years ago
The function is y=6x.<br><br> Find the horizontal asymptote of the curve.
Lynna [10]

Answer:

y=-6x/square root (4x^2-160

Step-by-step explanation:

hope this helps please mark me brainliest

6 0
2 years ago
Read 2 more answers
Mopeds (small motorcycles with an engine capacity below 50cm3) are very popular in Europe because of their mobility, ease of ope
d1i1m1o1n [39]

Answer:

a) 96.64% probability that maximum speed is at most 50 km/h

b) 24.67% probability that maximum speed is at least 48 km/h

c) 86.64% probability that maximum speed differs from the mean value by at most 1.5 standard deviations

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 46.8, \sigma = 1.75

A. What is the probability that maximum speed is at most 50 km/h?

This is the pvalue of Z when X = 50. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{50 - 46.8}{1.75}

Z = 1.83

Z = 1.83 has a pvalue of 0.9664

96.64% probability that maximum speed is at most 50 km/h.

B. What is the probability that maximum speed is at least 48 km/h?

This is 1 subtracted by the pvalue of Z when X = 48.

Z = \frac{X - \mu}{\sigma}

Z = \frac{48 - 46.8}{1.75}

Z = 0.685

Z = 0.685 has a pvalue of 0.7533

1 - 0.7533 = 0.2467

24.67% probability that maximum speed is at least 48 km/h.

C. What is the probability that maximum speed differs from the mean value by at most 1.5 standard deviations?

Z = 1.5 has a pvalue of 0.9332

Z = -1.5 has a pvalue of 0.0668

0.9332 - 0.0668 = 0.8664

86.64% probability that maximum speed differs from the mean value by at most 1.5 standard deviations

6 0
3 years ago
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