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3 years ago

P = 9r +3q Work out the value of P when r = 6 and q = -4 P =

Mathematics

2 answers:

disa [49]3 years ago

6 0

Answer:

p= 9(6)+3(-4)

p= 42

hope this help

Sergeu [11.5K]3 years ago

4 0

Answer:

Step-by-step explanation:

P=9r+3q

When q equals to a negative 4 and when r is aswell the number 6.It means to substitute

P=9(6)+3(-4)

p=54-12

p=42

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I NEED HELP ASAP!!!!!!! PLEASE HELP ME!!!!!!!!!

aniked [119]

Answer:

a = 33 degrees, b = 147 degrees

Step-by-step explanation:

The sum of all the angles in a triangle is 180 degrees, and to solve for the angle on the other side of 109 degrees is 71 degrees, so to solve for a, have 180 minus 71 and 76. Then the sum of 71 and 76 is angle b since its the result of a subtracting from 180.

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3 years ago

3. The total cost for 9 bracelets, including shipping was $72. The shipping charge was $9. Define your variable and write an equ

ikadub [295]

Answer:

The equation that models the cost of each bracelet is $72=9x+9$ . Cost of each bracelet is $7.

Step-by-step explanation:

Let the cost of each bracelet is defined by the variable x.

Cost of 9 bracelet is 9x. The shipping cost is $9. Therefore the total cost of 9 bracelets, including shipping is

$\text{Total Cost}=9x+9$

The total cost for 9 bracelets, including shipping is $72.

$72=9x+9$

Subtract 9 from both sides

$72-9=9x+9-9$

$63=9x$

Divide both sides by 9.

$7=x$

Therefore the cost of each bracelet without shipping changes is $7.

8 0

3 years ago

What are the solutions to the following system? StartLayout Enlarged left-brace 1st row negative 2 x squared + y = negative 5 2n

Yakvenalex [24]

Answer:

$(\sqrt{2},-1),(-\sqrt{2},-1)$

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

Step-by-step explanation:

we have

$-2x^{2} +y=-5$ ----> equation A

$y=-3x^{2} +5$ -----> equation B

solve by substitution

substitute equation B in equation A

$-2x^{2} +(-3x^{2} +5)=-5$

solve for x

$-5x^{2} +5=-5$

$-5x^{2}=-10$

$x^{2}=2$

$x=\pm\sqrt{2}$

<em>Find the value of y</em>

$y=-3x^{2} +5$

For $x=\sqrt{2}$ ----> $y=-3(\sqrt{2})^{2} +5=-1$

For $x=-\sqrt{2}$ ----> $y=-3(-\sqrt{2})^{2} +5=-1$

therefore

The solutions are

$(\sqrt{2},-1),(-\sqrt{2},-1)$

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

8 0

3 years ago

Read 2 more answers

Very confused & don't understand, if anyone can explain I appreciate it!

Usimov [2.4K]

<span>oh i get it well to make two equations equal you have to find something that fits in x. you see the eqal sign? that is seperating the two equations that you have to make equal </span>

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3 years ago

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Solve r=s/17−t for t

mamaluj [8]

T=-r+s/17

Explanation:

6 0

3 years ago