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Delvig [45]
3 years ago
13

Two equiangular decagons are congruent. Sometimes/Always/Never

Mathematics
1 answer:
OLga [1]3 years ago
4 0

Answer:

Two equiangular decagons are sometimes congruent.

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Two fifths times five
snow_lady [41]
\frac{2}5\times5=\frac{10}5=\boxed{2}

Note that the ÷5 and the ×5 cancel out.
7 0
3 years ago
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X = 11<br> 1-4x + y = -23<br> Solve the system of equations.
mash [69]
Y=20
You can plug in 11 for X and do the math from there on
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3 years ago
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the diagram below shows the angles formed by some intersecting lines. give that m&lt;8=34, m&lt;9=40, and mm&lt;3=62, find the m
MrMuchimi

Answer:

m<4 = 44°

Step-by-step explanation:

m<8 = 34°

m<9 = 40°

m<3 = 62°

m<2 = 34° + 40° (exterior angle theorem of a triangle)

m<2 = 74°

m<3 + m<4 + m<2 = 180° (sum of ∆)

62° + m<4 + 74° = 180° (substitution)

m<4 + 136° = 180°

m<4 = 180 - 136 (substitution property of equality)

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5 0
3 years ago
What is the volume of this rectangular prism?
Anton [14]

Answer:

15.625

Step-by-step explanation:

V=wxhxl=2.5x2.5x2.5=15.625

7 0
3 years ago
If csc 0=8÷7 which equation represents cot 0
Dahasolnce [82]

Answer: Cot\theta =\frac{\sqrt{15} }{7}

Step-by-step explanation:

Since, given cosec\theta=\frac{8 }{7}

And we know that Cot\theta=\sqrt{cosec^2\theta-1}

Therefore, Cot\theta=\sqrt{cosec^2\theta-1} = \sqrt{(8/7)^2-1}= \sqrt{64/49-1}

⇒Cot\theta=\sqrt{64-49/49}=\sqrt{15/49}=\sqrt{15}/7

Thus,  Cot\theta =\frac{\sqrt{15} }{7}


4 0
4 years ago
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