3 years ago

Two equiangular decagons are congruent. Sometimes/Always/Never

Mathematics

1 answer:

OLga [1]3 years ago

4 0

Answer:

Two equiangular decagons are sometimes congruent.

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Two fifths times five

snow_lady [41]

$\frac{2}5\times5=\frac{10}5=\boxed{2}$

Note that the ÷5 and the ×5 cancel out.

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3 years ago

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X = 11<br> 1-4x + y = -23<br> Solve the system of equations.

mash [69]

Y=20
You can plug in 11 for X and do the math from there on

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3 years ago

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the diagram below shows the angles formed by some intersecting lines. give that m<8=34, m<9=40, and mm<3=62, find the m

MrMuchimi

Answer:

m<4 = 44°

Step-by-step explanation:

m<8 = 34°

m<9 = 40°

m<3 = 62°

m<2 = 34° + 40° (exterior angle theorem of a triangle)

m<2 = 74°

m<3 + m<4 + m<2 = 180° (sum of ∆)

62° + m<4 + 74° = 180° (substitution)

m<4 + 136° = 180°

m<4 = 180 - 136 (substitution property of equality)

m<4 = 44°

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3 years ago

What is the volume of this rectangular prism?

Anton [14]

Answer:

15.625

Step-by-step explanation:

V=wxhxl=2.5x2.5x2.5=15.625

7 0

3 years ago

If csc 0=8÷7 which equation represents cot 0

Dahasolnce [82]

Answer: $Cot\theta =\frac{\sqrt{15} }{7}$

Step-by-step explanation:

Since, given $cosec\theta=\frac{8 }{7}$

And we know that $Cot\theta=\sqrt{cosec^2\theta-1}$

Therefore, $Cot\theta=\sqrt{cosec^2\theta-1} = \sqrt{(8/7)^2-1}= \sqrt{64/49-1}$

⇒ $Cot\theta=\sqrt{64-49/49}=\sqrt{15/49}=\sqrt{15}/7$

Thus, $Cot\theta =\frac{\sqrt{15} }{7}$

4 0

4 years ago

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