All categories

3 years ago

Two equiangular decagons are congruent. Sometimes/Always/Never

Mathematics

1 answer:

OLga [1]3 years ago

4 0

Answer:

Two equiangular decagons are sometimes congruent.

You might be interested in

F(x) = 3x-1 and g(x)=2x^2

Law Incorporation [45]

Answer:

See below

Step-by-step explanation:

a. here you are to multiply the two functions together:

$(3x-1)(2x^{2} )=6x^{3}-2x^{2}$

b. here you are to subtract g from f:

$(3x-1)-(2x^{2})=-2x^{2}+3x-1$

c. here you are to compose g into f. In other words, pick up the whole g function and plug it into f wherever you see an x:

$3(2x^{2} )-1=6x^{2} -1$

d. here you are compose f into g. In other words, pick up the whole f function and plug it into g wherever you see an x:

$2(3x-1)^2$

You now have to FOIL out the (3x-1) like so:

$2[(3x-1)(3x-1)]$

which gives you

$2(9x^{2} -6x+1)$

Distribute in the 2 and you'll end up with the answer:

$18x^{2} -12x+2$

3 0

3 years ago

What is the value of d + e + f when d = 20, e = –4 and f = –2?

saw5 [17]

20 - 4 - 2 = 14. A negative number is just like subtracting it.

5 0

2 years ago

kherson [118]

Answer:

$25.57

Step-by-step explanation:

First, you have to multiply $5.29 by 2 because she wants to spend $5.29 on 2 pairs of socks.

5.29 * 2 = $10.58

Then you want to add $10.58 and $14.99 together.

$10.58 + $14.99 = $25.57

3 0

3 years ago

Can I get some help..please?

krek1111 [17]

Answer:

-2 and 21/50

Step-by-step explanation:

PEMDAS says that paranthases go first, so we solve 2 and 1/5 minus 33/12. 2 and 1/5 simplifies to the improper fraction, 11/5. Then we find a common denominater between 11/5 and 33/12 to get 60. 11/5=132/60, and 33/12=165/60. (132/60)-(165/60)=-33/60. Then we multipl that by 4 and 2/5, which can simplify to the improper fraction, 22/5. (22/5)*(-33/60) is -726/300, and simplifies to -2 and 21/50. Hope this helps!

7 0

2 years ago

What is the volume of this equation?

Pachacha [2.7K]

Answer:

Volume ≈ 33.33 cubic feet

Step-by-step explanation:

The question is:

<em>Find the volume of a right square pyramid with base square edges measuring 5 feet each and a height of the pyramid be 4 feet.</em>

<em />

So, the base is a square with side length 5 feet.

And the height of the pyramid is 4 feet.

The volume of a pyramid is given by the formula:

$V=\frac{a^2 h}{3}$

Where

a is the square base side length (given as 5)

h is the height of the pyramid (given as 4)

Now we substitute and find the value:

$V=\frac{a^2 h}{3}\\V=\frac{(5)^2 (4)}{3}\\V=33.33$

The volume is around 33.33 cubic feet

5 0

2 years ago