Complete question :
The birthweight of newborn babies is Normally distributed with a mean of 3.96 kg and a standard deviation of 0.53 kg. Find the probability that an SRS of 36 babies will have an average birthweight of over 3.9 kg. Write your answer as a decimal. Round your answer to two places after the decimal
Answer:
0.75151
Step-by-step explanation:
Given that :
Mean weight (m) = 3.96kg
Standard deviation (σ) = 0.53kg
Sample size (n) = 36
Probability of average weight over 3.9
P(x > 3.9)
Using the z relation :
Zscore = (x - m) / (σ / √n)
Zscore = (3.9 - 3.96) / (0.53 / √36)
Zscore = - 0.06 / 0.0883333
Zscore = −0.679245
Using the Z probability calculator :
P(Z > - 0.679245) = 0.75151
= 0.75151
Step-by-step explanation:
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Answer:
The equation has a maximum value with a y-coordinate of -21.
Step-by-step explanation:
Given
Required
The true statement about the extreme value
First, write out the leading coefficient
means that the function would be a downward parabola;
Downward parabola always have their vertex on top of the parabola and as such, the function has a maximum value.
The maximum value is:
Where:
So, we have:
Substitute in
<em>Hence, the maximum is -21.</em>
1.a)add
B) substract
C) multiply
D) one
2) 1002=1.002×10^3
3)2.8×10^-3 < 2.5×10^-2 < 1.2×103 <4×103
Answer:
2x^5log=1/6
Step-by-step explanation:
using the natural log (e), we were able to give the power of 5 to 2x and then take it out from the parantheses
