Ask question

Ask question

All categories

erma4kov [3.2K]

4 years ago

11

Which expression, when simplified, is equal to 7p? A) 9p – 2pq – 7p – 5p + 2pq B) 9p – 2pq – 7p + 5p – 2pq C) 9p + 2pq – 7p + 5p

– 2pq D) 9p + 2pq + 7p + 5p – 2pq E) 9p + 2pq – 7p + 5p + 2pq

1 answer:

WINSTONCH [101]4 years ago

7 0

Answer:C

Step-by-step explanation:

2pq - 2pq is zero. B and E have no zero pq coefficient.

p(9-7+5) = 7p

You might be interested in

Find the slope of the line that passes through the following points (2,5) (5,11)

adoni [48]

Answer:

the slope is 2

Step-by-step explanation:

take y2 and y1 and subtract them, 11 - 5 = 6

then take x2 and x1 and subtract them, 5 - 2 = 3

then divide those 2 numbers, 6/3 and you get 2

4 0

3 years ago

Read 2 more answers

You are on a business trip in Great Britain. Great Britain uses the pound for currency. The exchange rate is 1 British Pound is

artcher [175]

If the exchange rate is $1.46 and you are exchanging $100, you will receive 146 pounds.

8 0

3 years ago

Read 2 more answers

Name a pair of adjacent angles. explain why they are adjacent. Name a pair of acute vertical angles. Name a pair of supplementar

Anna71 [15]

The 41° and the 90° are adjacent. They are adjacent because they are touching each other side by side. That is the angles SUR and SUT

Angle SUR is acute, because it is 41° and it less than 90°. Same as angle PUQ. Angle PUR = Angle SUR, both are vertically opposite, therefore PUR is also 41°.

Angles TUQ and QUN are both supplementary because they both add up to 180°, which is the straight line TUN.

6 0

3 years ago

the weight of an object on mars varies directly as the weight of the object on earth a 90 pound object on earth weighs 34 pounds

Mariulka [41]

We have been given that the weight of an object on the mars varies directly as the weight of the object on earth.

Let y be weight of an object on Mars and x be weight of an object on Earth.

$\\
y=kx$

We have been given that the weight of an object on Mars is 34 pounds and weight of the same object on Earth is 90 pounds.

Putting the given values in equation we get

$\\
34=k(90)\\
\\
k=\frac{34}{90}=\frac{17}{45}$

Therefore, our equation now becomes

$\\
y= \frac{17}{45}x$

Now we have been given that the weight of an object on Earth is 135 pounds and we have to find the weight of the same object on Mars,

We have been given that $\\
x=135$

Putting the given values in our equation we get

$\\
y= \frac{17}{45}(135)=\frac{17\cdot 135}{45}=17\cdot 3 = 51$

Therefore weight of the object on Mars will be 51 pounds.

7 0

4 years ago

Read 2 more answers

What expression is equivalent to 12/5x-2

Aleksandr [31]

One expression that is equivalent to 12/5x-2 is 2.4x-2 if divided :)

6 0

2 years ago