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Levart [38]
3 years ago
12

What is an equivalent expression to −56z+28

Mathematics
2 answers:
lara [203]3 years ago
8 0

Answer:

(

2

z

−

1

)

Step-by-step explanation:

Inga [223]3 years ago
3 0

-56z:28

z equal to 28/56

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Please answer correctly, its in the attachment.
tino4ka555 [31]

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Step-by-step explanation:

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3 years ago
Can someone please solve for x:
BabaBlast [244]
Make the denominator into 10x:
5x/10x +20/10x=x(x+4)/10x
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(x-5)(x+4)=0
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the third choice is correct. 
3 0
3 years ago
Read 2 more answers
Joe borrowed 2,000 dollars from the bank at a rate of 7% simple interest per year.How much interest did he pay in 5 years​
Karolina [17]

Answer:

$700

Step-by-step explanation:

First you find what 7% of $2000 is,

(2000/100)7=140

$140 per year interest, over the course of five years that would be $700

140)5

8 0
3 years ago
ASAP! I NEED THIS DONE AS QUICKLY AS POSSIBLE WITH WORKING OUT
Elza [17]

Answer:

See explanation.

Step-by-step explanation:

Let us first analyze some principle theory. By definition we know that the velocity ( v ) is a function of a distance  ( d ) covered in some time  ( t ), whilst acceleration ( a ) is the velocity achieved in some time. These can also been expressed as:

v = \frac{d}{t}\\ and a=\frac{v}{t}

We also know that both velocity and acceleration are vectors (therefore they are characterized by both a magnitude and a direction). Finally we know that given a position vector we can find the <u>velocity and the acceleration</u>, by differentiating the vector with respect to time, once and twice, respectively.

Let us now solve our problem. Here we are givine the Position vector of a particle P (in two dimensional space of i-j ) as:

r=(3t^3-t+3)i+(2t^2+2t-1)j         Eqn.(1)

Let us solve.

<u>Part (a) Velocity: </u><u>we need to differentiate Eqn.(1) with respect to time as:</u>

v(t)=\frac{dr}{dt}\\\\ v(t)=[(3)3t^2-1]i+[(2)2t+2]j\\\\v(t)=(9t^2-1)i+(4t+2)j            Eqn.(2)

<u>Part (b) Acceleration: </u><u>we need to differentiate Eqn.(2) with respect to time as:</u>

<u />a(t)=\frac{dv}{dt}\\ \\a(t)=[(2)9t]i+4j\\\\a(t)=(18t)i+4j<u />

<u />

Thus the expressions for the velocity and the acceleration of particle P in terms of t are

v(t)=(9t^2-1)i+(4t+2)j   and   a(t)=(18t)i+4j

6 0
4 years ago
A toy store buys action figures from a factory for $8.00 per action figure. If they mark-up the toys 110% before selling them, w
polet [3.4K]

Answer:

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Step-by-step explanation:

4 0
4 years ago
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