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3 years ago

13

Which of the following best describes a group?

Computers and Technology

1 answer:

ExtremeBDS [4]3 years ago

5 0

Answer:

I would say it would be a cluster of related commands.

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Explain demand paging with a proper example

julia-pushkina [17]

<h2><em><u>Demand</u></em><em><u> </u></em><em><u>paging</u></em><em><u> </u></em><em><u>:</u></em></h2>

<h3><em>In computer operating systems, demand paging (as opposed to anticipatory paging) is a method of virtual memory management. In a system that uses demand paging, the operating system copies a disk page into physical memory only if an attempt is made to access it and that page is not already in memory (i.e., if a page fault occurs). It follows that a process begins execution with none of its pages in physical memory, and many page faults will occur until most of a process's working set of pages are located in physical memory. This is an example of a lazy loading technique.</em></h3>

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4 years ago

Objectives ** WILL GIVE BRAINIST PLEASE**

mamaluj [8]

Answer:

of which std this question is

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3 years ago

Read 2 more answers

Which storage con be used<br>as permanent storage<br>a) Rom<br>6) RAM, © main memery

Veseljchak [2.6K]

Answer:

ROM

Explanation:

Data in ROM does not erase itself when the computer is shut down. The data is permentely written and stored.

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3 years ago

For your biology class, you will be giving a presentation of the findings of a plant

kaheart [24]

Answer:

PowerPoint

Explanation:

It is dedicated for presentation.

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4 years ago

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Consider sending a 2400-byte datagram into a link that has an mtu of 700 bytes. suppose the original datagram is stamped with th

Feliz [49]

Explanation:

Let, DG is the datagram so, DG= 2400.

Let, FV is the Value of Fragment and F is the Flag and FO is the Fragmentation Offset.

Let, M is the MTU so, M=700.

Let, IP is the IP header so, IP= 20.

Let, id is the identification number so, id=422

Required numbers of the fragment = $[\frac{DG-IP}{M-IP} ]$

Insert values in the formula = $[\frac{2400-20}{700-20} ]$

Then, = $[\frac{2380}{680} ]$ = $[3.5]$

The generated numbers of the fragment is 4

If FV = 1 then, bytes in data field of DG= $720-20 = 680$ and id=422 and FO=0 and F=1.

If FV = 2 then, bytes in data field of DG= $720-20 = 680$ and id=422 and FO=85 $(85*8=680 bytes)$ and F=1.

If FV = 3 then, bytes in data field of DG= $720-20 = 680$ and id=422 and FO=170 $(170*8=1360 bytes)$ and F=1.

If FV = 4 then, bytes in data field of DG= $2380-3(680) = 340$ and id=422 and FO=255 $(255*8=2040 bytes)$ and F=0.

3 0

4 years ago