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Vedmedyk [2.9K]
3 years ago
15

Which number shows 460,593 rounded to the nearest hundred thousand?

Mathematics
1 answer:
Mariulka [41]3 years ago
4 0
Your answer is C. 500,000
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6^x+8=17^2x-2 can I have help
bazaltina [42]
6^{x+8}=17^{2x-2}\ \ \ \ \ \ |both\ sides\ log_6\\\\log_66^{x+8}=log_617^{2x-2}\\\\x+8=(2x-2)log_617\\\\x+8=2xlog_617-2log_617\\\\x-2xlog_617=-2log_617-8\\\\x(1-2log_617)=-2log_617-8\ \ \ \ |divide\ both\ sides\ by\ (1-2log_617)\\\\x=\frac{-2log_617-8}{1-2log_617}\\\\x=\frac{-(log_617^2+8)}{-(log_617^2-1)}\\\\x=\frac{log_6289+8}{log_6289-1}
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4 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B6y%2B7%7D%3D5%2B%5Csqrt%7By-3%7D%20%5C%5CI%20get%20how%20to%20begin%20this%20but%20h
PilotLPTM [1.2K]

Answer:

\sqrt{6y+7} -\sqrt{y-3} =5\\(\sqrt{6y+7} -\sqrt{y-3} )^2=5^2\\\sqrt{6y+7} ^2+\sqrt{y-3} ^2-2\sqrt{(6y+7)(y-3)} =25\\6y+7+y-3-25=2\sqrt{(6y+7)(y-3)} \\7y-21=2\sqrt{(6y+7)(y-3)} \\(7y-21)^2=(2\sqrt{6y^2-18y+7y-21} )^2\\49y^2+441-294y=4(6y^2-11y-21)\\49y^2+441-294y=24y^2-44y-84\\49y^2-24y^2+441+84-294y+44y=0\\25y^2-250y+525=0\\25(y^2-10y+21)=0\\y^2-10y+21=0\\y^2-7y-3y+21=0\\y(y-7)-3(y-7)=0\\(y-7)(y-3)=0\\y-7=0 or y-3=0\\y=7 ,y=3

Step-by-step explanation:

8 0
3 years ago
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An expression is shown. 590.92 - 219.38 What is the value of the expression?​
statuscvo [17]

371.54 is the answer :)

3 0
3 years ago
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Ques<br><br> The set of values (63, 64, 65, 66} represents solutions of which inequality?
Ostrovityanka [42]

Answer: 63 < N ≤ 66

Step-by-step explanation:

We have the set:

(66, 64, 65, 66]

First.

When we have an end with the signs "(" or ")" means that the element near the sign does not belong to the set, this would be an "open" end. Usually used for the symbols > and <

While the sign "[" or "]" (in some cases the symbols { and } are used instead)

means that the value next to it are included in the set. Usually used for the symbols ≤ and ≥.

Then in the set: (63, 64, 65, 66} the value 63 does not actually belong, and value 66 does belong.

Then this set is written as:

63 < N ≤ 66

Such that N is an integer number.

7 0
3 years ago
The mass of an electron is approximately 9.11 × 10 -28 grams. Find the mass of 401,000,000 electrons. 3.65311 × 10-19 grams 3.65
NNADVOKAT [17]

Answer:

Total\ Mass = 3.65311 * 10^{-19} grams

Step-by-step explanation:

Given

Mass = 9.11 * 10^{-28}g

Required

Determine the mass of 401,000,000 electrons

To do this, we simply multiply the mass of 1 electron by the number of electrons.

This gives:

Total\ Mass = 401,000,000 * 9.11 * 10^{-28}

Total\ Mass = 3653110000 * 10^{-28}

Express 3653110000 as a standard form

Total\ Mass = 3.65311 * 10^9 * 10^{-28}

Apply law of indices:

Total\ Mass = 3.65311 * 10^{9-28}

Total\ Mass = 3.65311 * 10^{-19}

Hence, the mass of 401000000 electrons is 3.65311 * 10^{-19}\ grams

4 0
3 years ago
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