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Arturiano [62]
4 years ago
6

4.79+ what=37 100-what=52.7

Mathematics
2 answers:
Bess [88]4 years ago
8 0
Question 1)

solve your equation step-by-step.

4.79+x=37100

Simplify both sides of the equation.

x+4.79=37100

Subtract 4.79 from both sides.

x+4.79−4.79=37100−4.79

x=37095.21


Question 2)


solve your equation step-by-step.

100−x=52.7

Simplify both sides of the equation

100−x=52.7

100+−x=52.7

−x+100=52.7

Subtract 100 from both sides.

−x+100−100=52.7−100

−x=−47.3

Divide both sides by -1.

−x−1=−47.3−1

x=47.3

Ber [7]4 years ago
6 0
 4.79 + x = 37
-4.79      -4.79        4.79 + 32.21=37
           x=32.21 
 
 100 - x =52.7
-100       -100       100- 47.3=52.7
         <u>-x</u>= -<u>47.3</u>
         -x     -x
           x= 47.3
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Answer:

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Step-by-step explanation:

<u>The complete question is</u>: In a survey of consumers aged 12 and​ older, respondents were asked how many cell phones were in use by the household.​ (No two respondents were from the same​ household.) Among the​ respondents, 215 answered​ "none", 280 said​ "one", 362 said​ "two", 149 said​ "three," and 140 responded with four or more. A survey respondent is selected at random. Find the probability that​ his/her household has four or more cell phones in use. Is it unlikely for a household to have four or more cell phones in​ use? Consider an event to be unlikely if its probability is less than or equal to 0.05.

We are given that among the​ respondents, 215 answered​ "none", 280 said​ "one", 362 said​ "two", 149 said​ "three," and 140 responded with four or more.

A survey respondent is selected at random.

As we know that the probability of any event is calculated as;

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Here, we have to find the probability that​ his/her household has four or more cell phones in use;

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Total number of respondents asked = 215 + 280 + 362 + 149 + 140 = 1146

<u>So, the required probability</u> = \frac{140}{1146}

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