To solve for proportion we make use of the z statistic.
The procedure is to solve for the value of the z score and then locate for the
proportion using the standard distribution tables. The formula for z score is:
z = (X – μ) / σ
where X is the sample value, μ is the mean value and σ is
the standard deviation
when X = 70
z1 = (70 – 100) / 15 = -2
Using the standard distribution tables, proportion is P1
= 0.0228
when X = 130
z2 = (130 – 100) /15 = 2
Using the standard distribution tables, proportion is P2
= 0.9772
Therefore the proportion between X of 70 and 130 is:
P (70<X<130) = P2 – P1
P (70<X<130) = 0.9772 - 0.0228
P (70<X<130) = 0.9544
Therefore 0.9544 or 95.44% of the test takers scored
between 70 and 130.
Answer:
- 4.7
Step-by-step explanation:
Step 1:
c - 1.5 + 6.8 = 0.6
Step 2:
c + 5.3 = 0.6
Step 3:
c = 0.6 - 5.3
Answer:
c = - 4.7
Hope This Helps :)
Answer:
-15e+14f-30
Step-by-step explanation:
First using distributive property to expand the first term:
-21e+14f-28+6e-2
Combining like terms:
-15e+14f-30
The answer is D.
(-3, -3), (-3, 2)
(7, -3), (7, 2)