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zhuklara [117]
3 years ago
12

Fg is the midsegment of isosceles ABC , and KM is the midsegment of trapeziod cdef. ef km dc. find measurements BC,GF,CD, KM

Mathematics
1 answer:
Iteru [2.4K]3 years ago
3 0
We need the picture. So do you. That's why it's printed right there.
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Radda [10]

Answer:

A

Step-by-step explanation:

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3 years ago
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Which is the interval notation represent the domain?
Kazeer [188]

Answer:

The first choice, (-\infty, 7) \cup (7, \infty).

Step-by-step explanation:

The dashed vertical line is a vertical asymptote. The x-coordinate of all points on this vertical asymptote are equal to 7. In other words, when the x-value of a point on the graph approaches 7, its y-value approaches infinity (or negative infinity.)

Either way, the graph is not defined for x = 7. The point 7 should thus be excluded from the domain of the graph.

The graph is apparently defined for all other x-values. The domain of the function should thus be all real numbers with the exception of x = 7. Here's how to write that in interval notation:

  • The set of all real numbers can be expressed as the interval (-\infty, \infty). Note that infinity \infty (or (- \infty) itself isn't a real number. The round brackets indicate that both endpoints are excluded from the from the interval.
  • The set of all real numbers less than (not equal to) 7 is (-\infty,7 ) (both ends are excluded.) The set of all real numbers greater than (not equal to) 7 is (7, \infty).
  • The set of all real numbers that is not equal to 7 is the union of all real numbers less than 7 and all real numbers greater than 7. The union operator \cup connects two intervals.

In other words, the domain is (-\infty, 7) \cup (7, \infty).

5 0
3 years ago
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inna [77]

Answer:

Answer choice A

Step-by-step explanation:

Use the slope intercept form y = mx + b to find the slope m and y-intercept b.

Slope = 4/3

y intercept = (0,-3)

Therefore the answer choice is A, 4/3 ; -3

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2 years ago
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Flauer [41]
A & b would be the congruent pair of angles
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3 years ago
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PLEASE HELP!!<br><br> Find the area of the sector.
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Answer:

B.

\frac{275\pi}{6}  {m}^{2}

Step-by-step explanation:

area \: of \: sector \: is \\  \frac{the \: angle}{360}  \times \pi {r}^{2}  \\ hence \: we \: have \\  \frac{165}{360}  \times  {(10m)}^{2}  =  \frac{275\pi}{6}  {m}^{2}

7 0
3 years ago
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