Here it is given that the width is x ft and total length of the fence is 2400 ft .
Let the length be y ft
So we have
Let A represents area, and area is the product of length and width .
So we get
Substituting the value of y, we will get
Second part
The area is maximum at the vertex, and vertex is
And
And that's the required dimensions .
Answer:
1) ∫ x² e^(x) dx
4) ∫ x cos(x) dx
Step-by-step explanation:
To solve this problem, eliminate the choices that can be solved by substitution.
In the second problem, we can say u = x², and du = 2x dx.
∫ x cos(x²) dx = ∫ ½ cos(u) du
In the third problem, we can say u = x², and du = 2x dx.
∫ x e^(x²) dx = ∫ ½ e^(u) du
Answer:
0.318
Step-by-step explanation:
Tony’s club is selling oranges to raise money. For every box they sell, they get 1 1/8 dollars profit. They have sold 75 boxes already. How many more boxes must they sell to raise 180 dollars?
Answer: We are given:
The amount of money Tony's club get for every box they sell 
dollar
They amount of money Tony's club has raised by selling 75 boxes is:
dollars
The amount of money Tony's club is required to raise = 180 dollars
The remaining need to be raised is :
dollars
Therefore, the number of more boxes to be sold are:
Hence, 85 more boxes they must sell to raise 180 dollars
Answer:
This can be solved by using the empirical rule for a normal distribution.
Step-by-step explanation:
A. The number of skateboards given is one standard deviation above the mean. Approximately 68% of the data points lie within the range plus and minus one standard deviation of the mean. Therefore the required percentage is:
68 + 16 = 84%.
B. The given number of skateboards is two standard deviations above the mean. Approximately 95% of the data points lie within the range plus and minus two standard deviations of the mean. Therefore the required percentage is:
5/2 = 2.5%
C.The given number of skateboards is one standard deviations below the mean. Therefore the required percentage is:
16%.
