Question

What is the volume of a hemisphere with a radius of 40.7 in, rounded to the nearest tenth of a cubic inch?

Answer 1

Answer:

$(\frac{4}{3} \pi 40.7^{3})/2$

$\pi =3.14$

$(4*3.14*40.7^{3} )/3 = 282,261.5$

$(282,261.5)/2 = 141,130.7 in^{3}$

Step-by-step explanation:

1. Volume of sphere

$V=\frac{4}{3} \pi r^{3}$

2. Volume of hemisphere

$V=(\frac{4}{3} \pi r^{3} )/2$