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forsale [732]
3 years ago
12

A computer code is based on the prime facttorization of 160. find the prime factorization of 160

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
3 0
Prime factorization of 160 = 2 x 2 x 2 x 2 x 2 x 5
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Pls help me, I really dont understand
Stella [2.4K]

Answer:

-2.5x-.5

y=\frac{2}{3}x-1

draw the dotted line (3/7)x-3 and shade below it

Step-by-step explanation:

First, we need the slope

Use the slope formula:

\frac{Y_2-Y_1}{X_2-x_1}=\frac{2-(-8)}{-1-3}=\frac{10}{-4}=-2.5

so we have

y= -2.5x+b

Solve for b by plugging in coordiantes

-8= -2.5(3)+b

-8= -7.5+b

b= -.5

Put it together and get -2.5x-.5

2.)

A line is parallel to another line if they have the same slope (and different y intercepts)

So in the formula y=mx+b we knowe that m= 2/3

Now it's just a matter of solving for B

plug in the required coordinate to do this

-1=(2/3)*0+b

-1= b

Put it all together to get

y=\frac{2}{3}x-1

3.)

put this into slope intercept form

3x-7y>21

3x-21 > 7y

(3/7)x-3 >y

To graph this just draw a dotted line with the equation (3/7)x-3 and shade everything below it (use de_smos if you're stuck)

7 0
3 years ago
Divide. −36/−8 Enter your answer as a mixed number, in simplified form, in the box.
Pavel [41]

Answer:

= 4 whole  1/2

Step-by-step explanation:

Given that:

= −36/−8

"-" signs will be cancelled out with each other so

= 36/8

By reducing to lowest term

= 9/2

When writing into mixed form:

quotient = 4,   remainder = 1,  divisor = 2  so:

= 4  1/2

i hope it will help you!

8 0
3 years ago
One bar of candy A and two bars of candy B have 774 calories. Two bars of candy A and one bar of candy B contains 786 calories.
vampirchik [111]
◆ Define the variables:

Let the calorie content of Candy A = a
and the calorie content of Candy B = b

◆ Form the equations:

One bar of candy A and two bars of candy B have 774 calories. Thus:

a + 2b = 774

Two bars of candy A and one bar of candy B contains 786 calories

2a + b = 786

◆ Solve the equations:

From first equation,
a + 2b = 774
=> a = 774 - 2b

Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie

◆ Find caloric content:

Caloric content of candy B = 254 calorie

Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie
5 0
3 years ago
What equals c? <br><br> c- 7.6= -4
lord [1]
The answer is...
C = 7.6 
5 0
3 years ago
Read 2 more answers
Solve for X question 14
prisoha [69]

Answer:

x=2

Step-by-step explanation:

hope this helps

not sure if im right <3

4 0
2 years ago
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