ABCD is a square . the bisector of angle DBC cuts AC and CD at E and F respectively.Prove that BFx CE = BE x DF

The point A (-7,5) is reflected over the line x = -5, and then is reflected over the line x= 2. What are the coordinates of

liubo4ka [24]

Answer:

(7, 5) is the final reflection of the point.

Step-by-step explanation:

We are given point A(-7, 5) which is first reflected over the line $x= -5$ .

The minimum distance of the point A(-7, 5) from the line $x= -5$ is 2 units across the horizontal path (No change in y coordinate).

Point A lies 2 units on the left side of the line $x= -5$ .

So, its reflection will be 2 units on the right side of $x= -5$ .

Let its reflection be A' which has coordinates as (-5+2,5) i.e. (-3, 5).

Now A'(-3, 5) is reflected on the line $x=2$ .

The minimum distance of the point A'(-3, 5) from the line $x=2$ is 5 units across the horizontal path (No change in y coordinate).

Point A' lies 5 units on the left side of the line $x=2$ .

So, its reflection will be 5 units on the right side of $x=2$ .

Let its reflection be A'' which has coordinates as (2+5, 5) i.e (7, 5) is the final reflection of the point..

Please find attached image.

(7, 5) is the final reflection of the point.

5 0

4 years ago

What is a true statement about an isosceles right triangle?

Olegator [25]

The correct answer is D

3 0

3 years ago

Which fraction and equivalent decimal correctly shows the ratio of shaded circles to all circles

iren [92.7K]

Answer:

There are 12 circles and 6 of them are shaded. You have to find the ratio of how many circles are shaded and 6 circles are shaded and because, 6 is half of 12 the answer is 1 over 2=0.5

4 0

4 years ago

An acute angle θ is in a right triangle with cos θ = nine tenths. What is the value of sec θ?

pshichka [43]

We have
$\cos \theta=\frac{9}{10}$

For secant, we use
$\sec \theta=\frac{1}{\cos \theta}=\frac{1}{9/10}=\frac{10}{9}$

4 0

4 years ago

Read 2 more answers

Ryan and Marie had some marbles. if Ryan lost `15 marbles, he would have 4 times as many marbles as Marie. If Ryan lost 75 marbl

vaieri [72.5K]

Ryan's marbles = x
Marie has 4 times less marbles then Ryan would have if he lost 15 marbles (it means he would have x-15)
So, Marie marbles = (x-15):4
If Ryan lost 75 marbles (it means he would have x-75), he would have 1 1/2 times as many marbles as Marie.

We got an equation: $x-75=1\frac{1}2\cdot\frac{x-15}{4}$

          $x-75=\frac{3}2\cdot\frac{x-15}{4}$

Multiply both sides by 8:     $8x-8\cdot75=3\cdot(x-15)$

      $8x-600=3x-45$

Add 600 and subtract 3x on both sides:    $5x=555$

Divide both sides by 5:    $x=111$

Answer: Ryan have 111 marbles.

5 0

3 years ago