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2 years ago

8

a farmer examinea sample of 25 egg cartons and finds three cracked eggs whast the best predictions of the number of cartons with

cracked eggs in a delivery with 500 cartons? a 6 b 12 c 60 d 120

1 answer:

Lana71 [14]2 years ago

7 0

It's C because 500/25 = 20 and 20x3=60

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(х-y)²-3(x-y) how do you factorise this equation?

Kazeer [188]

Answer:

(x-y)(x-y-3)

Step-by-step explanation:

(x-y)² - 3(x-y)

take (x-y) common,

(x-y)(x-y-3)

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2 years ago

lapo4ka [179]

The answer is x=2

explanation:

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8 times 2 is 16, minus 11=5

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2 years ago

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2 years ago

Cosx+1/sin^3x=cscx/1-cosx

ANTONII [103]

<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).

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<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
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<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
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= [1 + cos(x)]/sin^3(x)
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8 0

3 years ago

A toy manufacturer wants to know how many new toys children buy each year. A sample of 1492 children was taken to study their pu

julia-pushkina [17]

By assuming the standard deviation of population 2.2 the confidence interval is 8.67 toys,8.94 toys.

Given sample size of 1492 children,99% confidence interval , sample mean of 8.8, population standard deviation=2.2.

This type of problems can be solved through z test and in z test we have to first find the z score and then p value from normal distribution table.

First we have to find the value of α which can be calculated as under:

α=(1-0.99)/2=0.005

p=1-0.005=0.995

corresponding z value will be 2.575 for p=0.995 .

Margin of error=z*x/d

where x is mean and d is standard deviation.

M=2.575*2.2/ $\sqrt{1492}$

=0.14

So the lower value will be x-M

=8.8-0.14

=8.66

=8.67 ( after rounding)

The upper value will be x+M

=8.8+0.14

=8.94

Hence the confidence interval will be 8.67 toys and 8.94 toys.

Learn more about z test at brainly.com/question/14453510

#SPJ4

8 0

1 year ago