Since in a pass code, the placement of the digits is
important, therefore this means that to solve for the total number of
possibilities we have to make use of the principle of Permutation. The formula
for calculating the total number of possibilities using Permutation is given
as:
P = n! / (n – r)!
where,
n = is the total amount of numbers to choose from = 20
r = is the total number of digits needed in the passcode =
4
Therefore solving for the total possibilities P:
P = 20! / (20 – 4)!
P = 20! / 16!
P = 116,280
<span>Hence there are a total of 116,280 possibilities of pass
codes.</span>
You want to solve for 'z'.
First combine like terms on either side of the equal sign.
Left side: 9z +2 ----> No like terms, leave alone
Right side: 6z - 10 -z - 4 ----> circle like terms and add
6z -z = 5z
-10 -4 = -14
Now the equation is:
9z + 2 = 5z - 14
Get all the 'z' terms on the left side and all the numbers on right side.
You can move a term to the other side if you flip the sign.
Move 5z to left side, flip the sign to -5z
Move '2' to right side, flip the sign to -2
9z - 5z = -2 -14
Add like terms
4z = -16
Divide by 4 on both sides
z = -4
Answer:
The point of maximum growth is at x=0.82
Step-by-step explanation:
Given a logistic function
we have to find the point of maximum growth rate for the logistic function f(x).
From the graph we can see that the carrying capacity or the maximum value of logistic function f(x) is 24 and the point of maximum growth is at 
i.e between 0 to 12
So, we can take and then solve for x.
⇒ 
⇒ 
⇒ 
⇒ log 3=-1.3x
⇒ -0.4771=-1.3.x ⇒ x=0.82
Hence, the point of maximum growth is at x=0.82
Answer:
hgfgbffvghgdv check g tunic
I think you are looking for the value of x
3x+2
-2
3x
X=3
