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3 years ago

What’s the answer to this ?

Mathematics

1 answer:

Katen [24]3 years ago

7 0

Answer:

4th one

Step-by-step explanation:

if you add them

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What is 4 - 2x = -2

vlada-n [284]

Answer:

x=3

Step-by-step explanation:

4-2x-4=-2-4

-2x=-6

\frac{-2x}{-2}=\frac{-6}{-2}

x=3

if i can get brainliest that would be great

8 0

3 years ago

2.548 rounded to the number 2.55 which place value did Marco round to

JulijaS [17]

The tens place because 4 and 8, 8 is over 5 so u round up then it is 254 rounded to the tens 55

7 0

3 years ago

Read 2 more answers

2. Yahir was going up the stairs when he noticed that the first step was taller, so he measured

goblinko [34]

Answer:

6.5

Step-by-step explanation:

This answer makes sense because i subtracted the 8 inches from the total 60 then i used the number i got in the result (52)then i divided 52 by 8 wich are the rest of the steps. getting 6.5

3 0

3 years ago

The answer is C that’s why it has a 1 pt in front Plz just help me explain how to get that

Ierofanga [76]

First lets get the formula for a triangular prism

$v =( \frac{1}{2} bh)h$

First lets plug in our numbers

$v =( \frac{1}{2} \times 7 \times 4)8.5$

It really doesnt matter how you multiply everything, but you end up with 119cubic feet.

3 0

3 years ago

What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

Step 2: Find Arc Length

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

4 0

3 years ago