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3 years ago

(5 + x) + (5 + x + 2)=

2 answers:

7 0

(5 + x) + (5 + x + 2)

First, simplify 5 + x + 2 to x + 7. / Your problem should look like: 5 + x + x + 7
Second, simplify. / Your problem should look like: 5 + 2x + 7
Third, simplify. / Your problem should look like: 2x + 12

Answer: 2x + 12

11Alexandr11 [23.1K]3 years ago

7 0

(5+x)+(5+x+2)

Combine Like Terms:

=5+x+5+x+2

=(x+x)+(5+5+2)

=2x+12

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2 years ago

Find the product. (3x 2 - 5x + 3)(3x - 2)

Romashka [77]

Answer:

9x^3-21x^2+19x-6

Step-by-step explanation:

First you have to distribute the first equation into the second since the two are being multiplied:

(3x^2-5x+3)(3x-2)

9x^3-6x^2-15^2+10x+9x-6

(simplify)

9x^3-21x^2+19x-6

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3 years ago

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nlexa [21]

Answer:

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Step-by-step explanation:

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3 years ago

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Radda [10]

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3 years ago

Let c be the curve which is the union of two line segments, the first going from (0, 0) to (4, 4) and the second going from (4,

victus00 [196]

First of all we need to find a representation of C, so this is shown in the figure below.

So the integral we need to compute is this:

$I=\int_c 4dy-4dx$

So, as shown in the figure, C = C1 + C2, so:

$I=\int_{c_{1}} (4dy-4dx)+\int_{c_{2}} (4dy-4dx)=I_{1}+I_{2}$

Computing first integral:

$c_{1}: y-y_{0}=m(x-x_{0}) \rightarrow y=x$

Applying derivative:

$dy=dx$

Substituting this value into $I_{1}$

$I_{1}=\int_{c_{1}} (4dx-4dx)=\int_{c_{1}} 0 \rightarrow \boxed{I_{1}=0}$

Computing second integral:

$c_{2}: y-y_{0}=m(x-x_{0}) \rightarrow y-0=-(x-8) \rightarrow y=-x+8$

Applying derivative:

$dy=-dx$

Substituting this differential into $I_{2}$

$I_{2}=\int_{c_{2}} 4(-dx)-4dx=\int_{c_{2}} -8dx=-8\int_{c_{2}}dx$

We need to know the limits of our integral, so given that the variable we are using in this integral is x, then the limits are the x coordinates of the extreme points of the straight line C2, so:

$I_{2}= -8\int_{4}^{8}}dx=-8[x]\right|_4 ^{8}=-8(8-4) \rightarrow \boxed{I_{2}=-32}$

Finally:

$I=\int_c 4dy-4dx=0-32 \rightarrow \boxed{I=-32}$

4 0

3 years ago