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Pie
3 years ago
7

PLEASE HELP WILL MARK BRAINLIEST PLZ PLZ PLZ!!

Mathematics
2 answers:
Lesechka [4]3 years ago
6 0

Answer:

7. C   8. E  9. is x=12

Step-by-step explanation:

180 divided by3 equals 60

60-12 =48

48/4 =12

juin [17]3 years ago
3 0
7) a

8) a, c, d

9) it is incorrect because he did not distribute the three to both terms. The correct work would be 3(4x+12) = 180 ; 12x+36 = 180 ; 12x = 144 ; x = 12
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Ms. Traynor’s class is taking a field trip to the zoo. The trip will cost 26$ for each student. There are 22 students in her cla
Minchanka [31]
Let’s estimate the students to 20 and the dollars to 25 so you would multiply 20 by 25 which equals 500 so $500 would be your answer
6 0
3 years ago
A rectangle has an area of 72 in². The length and the width of the rectangle are changed by a scale factor of 3.5. What is the a
kifflom [539]

Answer:

The area of the new rectangle is 882 in².

Step-by-step explanation:

Let l be the length and w be the width of the original rectangle,

So, the area of the original rectangle is,

A = l × w                  ( Area of a rectangle = Length × Width )

Given, A = 72 in²,

⇒ lw = 72 ------- (1),

Since, if the rectangle are changed by a scale factor of 3.5,

⇒ New length = 3.5 l,

And, new width = 3.5 w,

Thus, the area of the new rectangle = 3.5l × 3.5w

=(3.5)^2lw

=12.25\times 72  ( From equation (1) ),

= 882 in²

4 0
2 years ago
Does anyone know the answer to this? Algebra 2
natulia [17]

Answer:

Step-by-step explanation:

Sinθ = \frac{\text{Opposite side}}{\text{Hypotenuse}}

If, sinθ = -\frac{1}{2} and π < θ < \frac{3\pi }{2}

Since, sinθ is negative, angle θ will be in IIIrd quadrant.

And the measure of angle θ will be (180° + 30°)

θ = 210°

It's necessary to remember that tangent and cotangent of angle θ in quadrant III are positive.

Therefore, cos(210°) = -\frac{\sqrt{3} }{2}

tan(210°) = \frac{1}{\sqrt{3} }

csc(210°) = -\frac{1}{2}

sec(210°) = -\frac{2}{\sqrt{3} }

cot(210°) = √3

3 0
3 years ago
Describe the graph of the function. y = |x – 4| – 7
Lemur [1.5K]

Answer:

This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:

(x-4)=0 ===> x=4,

so that now you have to plot 2 functions!

For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:

|x-4| = -(x-4)=4-x

Then:

for x<=4, y = -x+4-7 = -x-3

for x=>4, (x-4) is positive, so no changes:

y= x-4-7 = x-11,

Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11

In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:

x=4 and x= 3 for y=-x-3

And just x=5 for y=x-11

The reason is that the absolute value is continuous, so x=4 works for both:

x=4===> y=-4-3 = -7

x==4 ====> y = 4-11=-7!

abs() usually have a cusp int he point where it is =0

Step-by-step explanation:

5 0
3 years ago
Someone please help me im in the middle of my quiz
ZanzabumX [31]

Answer:

the answer is B. you're welcome

8 0
2 years ago
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