Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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The given rational function is
We need to rationalize the denominator by multiplying both the numerator and the denominator by the conjugate of
which is
When we rationalize we obtain:
The denominator is now a difference of two squares:
We apply this property to get
This simplifies to
Or
I believe 24 is the correct answer
Answer:
7^12
Step-by-step explanation:
To divide an exponent by the other exponent, subtract the exponent from the denominator from the exponent above!
14-2= 12
Hope this helps :)
<em>CML is a supplementary angle</em>, it can't be a complementary angle because complentary angles are formed by two angles that equal 90 degrees, a
right angle. CMW is a right angle which is 90 degrees so that plus WML
has to equal more than 90, it must be a supplementary angle which is
formed by two angles that equal 180 degrees.
