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andrey2020 [161]
3 years ago
9

PLEASE ANSWER THIS FAST!!!!!Joseph is given the formula for the perimeter of a rectangle. The first step in solving for the vari

able L in the equation P = 2L + 2W is to: add the 2W to both sides of the equal sign. subtract the 2W to both sides of the equal sign. divide the 2 to both sides of the equal sign. None of these choices are correct.
Mathematics
1 answer:
ololo11 [35]3 years ago
8 0

Answer:

the first step is to subtract the 2W from each sides of the equal sides

Step-by-step explanation:

P=2L+2W

the first step is to subtract the 2W from each sides of the equal sides

P-2W=2L+2W-2W

P-2W=2L

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Help please! Need help solving
NISA [10]
For the perimeter you have to consider the EXTERNAL SHAPE ONLY:

a) the perimeter of half a circle WITHOUT ITS DIAMETER  is:
π.R - 2R → 3.14x1.5 - 2x1.5 → 1.71 cm

b) the perimeter of the rectangle WITHOUT THE UPPER SIDE is:
2.5+3+2.5 = 8 cm

Hence the perimeter of the figure is 1.71 + 8 = 9.71 cm

2) Area of the figure:
Area of half circle is π.R²/2 →3.14 x (1.5)²/2 → Area half circle = 3.5325 cm²
Area of rectangle = 2.5 x 3 = 7.5 cm²
Total area = 3.5325 + 7.5 = 11.0325 ≈ 11 cm²


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Step-by-step explanation:

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3 years ago
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What is the slope of (1,3) and (1,0)​
Dima020 [189]

Answer:

-3

Step-by-step explanation:

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7 0
3 years ago
A particle P, starting from rest at A, moves in a straight line ABCD. It accelerates uniformly at 5ms-2 from A to B. From B to C
Radda [10]
First, we find the time spent accelerating:
s = ut + 1/2 at²; u = 0
10 = 1/2 5t²
t = 2 seconds
Velocity at point B:
v = u + at; u = 0, a = 5 m/s², t = 2 s
v = (5)(2) = 10 m/s

Now, the same velocity is at C so we find the time decelerating to 0 in CD
v = u + at, v = 0, u = 10 m/s, a = -4 m/s²
0 = 10 - 4t
t = 2.5 seconds
Total time = time(AB) + time(BC) + time(CD)
20 = 2 + time(BC) + 2.5
time(BC) = 15.5 seconds

Distance = velocity x time
BC = 10 x 15.5
= 155 m
3 0
4 years ago
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