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3 years ago

Plz tell me this solution

Mathematics

2 answers:

Katyanochek1 [597]3 years ago

8 0

Answer:

A. x = 36

B. x = 10

C. x = 36

D. x = 25

E. x = 60

Step-by-step explanation:

A. Since it is a straight line, the total degrees will be 180. Add the two angle values and set them equal to 180.

2x + 3x = 180

5x = 180

x = 36

B. This is right angle, meaning that the total degrees will be 90. Add the two angle values and set them equal to 90.

4x + 5x = 90

9x = 90

x = 10

C. The angles are around a point, meaning that the total degrees will be 360. Add the angle values and set them equal to 360.

x + 2x + 3x + 4x = 360

10x = 360

x = 36

D. Like part A, the straight line has 180 total degrees. Add the angle values and set them equal to 180.

3x - 5 + x + 20 + 65 = 180

4x - 5 + 20 + 65 = 180

4x + 80 = 180

(4x + 80) - 80 = 180 - 80

4x = 100

(4x)/4 = 100/4

x = 25

E. Like part A, the angles around the point have 360 total degrees. Add the angles values and set them equal to 360.

x + 2x + 2x + 60 = 360

5x + 60 = 360

(5x + 60) - 60 = 360 - 60

5x = 300

(5x)/5 = 300/5

x = 60

mart [117]3 years ago

4 0

Answer:

a = 36°

b = 20°

c = 36°

d = 25°

e = 60°

Step-by-step explanation:

2x + 3x = 180° (angles on a straight line = 180°)

5x = 180°

X = 180 / 5

x = 36°

B) 4x + 5x = 90° (sum of two acute angles in a right angle triangle = 90°)

9x = 90

x = 90 / 9

x = 10°

C) 2x + x + 4x + 3x = 360° (sum of angles at a point = 360°)

10x = 360°

x = 360 / 10

x = 36°

D) (3x - 5) + (x + 20) + 65 = 180 (sum of angles on a straight line = 180)

Open brackets

3x - 5 + x + 20 + 65 = 180

4x + 80 = 180

Collect like terms

4x = 180 - 80

4x = 100

X = 100 / 4

x = 25°

x° + 60° + 2x° + 2x° = 360° (angle at a point = 360°)

5x° + 60° = 360°

Collect like terms

5x° = 360° - 60°

5x° = 300°

x = 300 / 5

x = 60°

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Step-by-step explanation:

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Start with the basic function f(x)=2x. If you have an initial value of 1, then you end up with the following iterations. f(1)=2*

denpristay [2]

<span>f(x)=2x

f(1)=2*1=2

f^2(1)=2*2*1=4

f^3(1) =2*2*2*1=8

1. If you continue this pattern, what do you expect would happen to the numbers as the number of iterations grows?

I expect the numbers continue growing multiplying each time by 2.

Check your result by conducting at least 10 iterations.

f^4(1) = f^3(1) * f(1) = 8*2 = 16

f^(5)(1) = f^4(1) * f(1) = 16 * 2 = 32

f^6 (1) = f^5 (1) * f(1) = 32 * 2 = 64

f^7 (1) = f^6 (1) * f(1) = 64 * 2 = 128

f^8 (1) = f^7 (1) * f(1) = 128 * 2 = 256

f^9 (1) = f^8 (1) * f(1) = 256 * 2 = 512

f^10 (1) = f^9 (1) * f(1) = 512 * 2 = 1024

2. Repeat the process with an initial value of −1. What happens as the number of iterations grows?

f(-1) = 2(-1) = - 2

f^2 (-1) = f(-1) * f(-1) = - 2 * - 2 = 4

f^3 (-1) = f^2 (-1) * f(-1) = 4 * (-2) = - 8

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f^5 (-1) = f^4 (-1) * f(-1) = 16 * (-2) = - 32

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</span>

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Inessa05 [86]

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Step-by-step explanation:

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3 years ago

Plz tell me this solution​

Plz tell me this solution