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lesya692 [45]
3 years ago
8

Write the following numbers in scientific notation: A) 2 304 550= B)376.092

Mathematics
1 answer:
kicyunya [14]3 years ago
4 0

The answer is b) 376.092

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LenKa [72]

Answer:

2

Step-by-step explanation:

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An iron ball is bobbing up and down on the end of a spring. The maximum height of the ball is 50 centimeters and its minimum hei
ololo11 [35]

Answer:

Step-by-step explanation:

Let us examine all options:

(a)

Lets verify for t = 0:

h(t = 0) = 7

This isn't allowable as 14 cm is the lower limit for the ball's motion.

This is rejected.

(b)

Let's verify for t = 0:

h(t = 0) = 14

Since at t = 0 sec, the ball is at its minimum, after 2 seconds, it should be at its maximum.

But h(t = 2) = 14, which doesn't satisfy the condition.

Hence, this is rejected.

(c)

Now, let's see at what time instance, the ball is at minimum in this case:

h(t) = 14 = 18sin(πt) + 32

∴ sin(πt) = -1

∴ πt = 3π/2

∴ t = 3/2 seconds

Hence, after 2 seconds, i.e. at 3.5 seconds, the ball should be at its maximum.

h(t = 3.5) = 18sin(3.5π) + 32 = -18 + 32 = 14, which doesn't satisfy the condition.

Hence, this is rejected,

(d)

Now, let's see at what time instance, the ball is at minimum in this case:

h(t) = 14 = 18sin(πt/2) + 32

∴ sin(πt/2) = -1

∴ πt/2 = 3π/2

∴ t = 3 seconds

Hence, after 2 seconds, i.e. at 5 seconds, the ball should be at its maximum.

h(t = 5) = 18sin(5π/2) + 32 = 18 + 32 = 50, which satisfies the condition.

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3 years ago
In a designated VIP seating section there must be an odd number of seats in each row and each row must have two more seats than
Vikki [24]

Let n be the total number of rows and there are x seats is the 1st row where x is an odd natural number.

As each row must have 2 more seats than the one before it, so

Number of seats in 2nd row = x+2

Number of seats in 3rd row = x+2+2=x+2x2

Number of seats in 4th row = x+2+2+=x+2x3

Similarly, the number of seats in (n-1)th row =x+2x(n-1)

the number of seats in n^{th} row, i.e last row  =x+2x n.

As the front row must have one-quarter of the total seats in the back 2 rows combined, so

x =\frac 1 4 ( x+2\times(n-1) + x+2\times n) \\\\\Rightarrow 4x=2x+4n-6 \\\\\Rightarrow 4x-2x=4n-6 \\\\\Rightarrow 2x=4n-6 \\\\\Rightarrow x=2n-3\cdots(i)

So, the number of seats in the 1st row, x, and the total number of seats, n, must satisfy the equation (i).

For x>0, n\geq 3.

So, for n=3 rows

The number of seats in the 1st row, x= 2x3-3=3.

The number of seats in the 2nd row, = 3+2=5 as in subsequent rows, there will be 2 more seats.

and the number of seats in the 3rd row (last row)=5+2=7.

n can have any integral values satisfying  n\geq 3.

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B. sqrt(441) is rational
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It's the 26th term of the sequence.

Hope this helps! :)

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4 years ago
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