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Jobisdone [24]
3 years ago
13

Assume that the total revenue received from the sale of x items is given​ by, ​R(x)equals34 ln (4 x plus 5 )​, while the total c

ost to produce x items is ​C(x)equalsx divided by 2. Find the approximate number of items that should be manufactured so that​ profit, ​R(x)minus​C(x), is a maximum.
Mathematics
1 answer:
katen-ka-za [31]3 years ago
5 0

Answer:

63 units

Step-by-step explanation:

The profit function P(x) is given by the revenue function minus the cost function:

P(x) = R(x) - C(x)\\P(x) = 34ln(x+5)-\frac{x}{2}

The number of units sold 'x' for which the derivate of the profit function is zero, is the number of units that maximizes profit:

P(x) = 34ln(x+5)-\frac{x}{2}\\P'(x) =0= \frac{34}{x+5}-\frac{1}{2}\\x+5=68\\x=63\ units

The number of units that should be manufactured so that​ profit is maximum is 63 units.

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The answer is x=-3

5-x=11+x
-11  -11             First subtract 11
-6-x=x          
+x  +x                Now add x to both sides
-6=2x 
~2 ~2                 Finally divide by 2
-3=x                   Your answer is x=-3

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Alfred buys a car for £15225 which depreciates in value at a rate of 0.25% per year.
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14,590

Step-by-step explanation:

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What is the address of the element 14 in Matrix D
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Step-by-step explanation:


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Let P=x^2+6<br> PLEASE SHOW WORK!!<br> 15 POINTS
stellarik [79]

Answer:

Step-by-step explanation:

P = x^2 + 6

(x^2+6)^2 - 21 = 4x^2 + 24\\(x^2+6)^2 - 4x^2 - 45 = 0

Solving for 4x^2:

P = x^2 +6

P - 6 = x^2

4(P - 6) = 4x^2

Substitution:

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4 0
3 years ago
Could the inverse of a non-function be a function? Explain or give an example.
Kitty [74]

Answer:

The inverse of a non-function mapping is not necessarily a function.

For example, the inverse of the non-function mapping \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\! is the same as itself (and thus isn't a function, either.)

Step-by-step explanation:

A mapping is a set of pairs of the form (a,\, b). The first entry of each pair is the value of the input. The second entry of the pair would be the value of the output.  

A mapping is a function if and only if for each possible input value x, at most one of the distinct pairs includes x\! as the value of first entry.

For example, the mapping \lbrace (0,\, 0),\, (1,\, 0) \rbrace is a function. However, the mapping \lbrace (0,\, 0),\, (1,\, 0),\, (1,\, 1) \rbrace isn't a function since more than one of the distinct pairs in this mapping include 1 as the value of the first entry.

The inverse of a mapping is obtained by interchanging the two entries of each of the pairs. For example, the inverse of the mapping \lbrace (a_{1},\, b_{1}),\, (a_{2},\, b_{2})\rbrace is the mapping \lbrace (b_{1},\, a_{1}),\, (b_{2},\, a_{2})\rbrace.

Consider mapping \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!. This mapping isn't a function since the input value 0 is the first entry of more than one of the pairs.

Invert \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\! as follows:

  • (0,\, 0) becomes (0,\, 0).
  • (0,\, 1) becomes (1,\, 0).
  • (1,\, 0) becomes (0,\, 1).
  • (1,\, 1) becomes (1,\, 1).

In other words, the inverse of the mapping \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\! would be \lbrace (0,\, 0),\, (1,\, 0),\, (0,\, 1),\, (1,\, 1) \rbrace\!, which is the same as the original mapping. (Mappings are sets. There is no order between entries within a mapping.)

Thus, \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\! is an example of a non-function mapping that is still not a function.

More generally, the inverse of non-trivial ellipses (a class of continuous non-function \mathbb{R} \to \mathbb{R} mappings, including circles) are also non-function mappings.

3 0
2 years ago
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