The side lengths of quadrilateral are 21 inches; 11 inches; 11 inches; 7 inches.
<u>SOLUTION:</u>
Given, the perimeter of a quadrilateral (four-side polygon) is 50 inches.
Let the length of shortest side be n inches. The longest side is three times as long as the shortest side.
That is, length of largest side = 3n inches
The other two sides are equally long and are 4 inches longer than the shortest side.
Then, length of remaining two sides = 4 + n inches
We have to find the length of all four sides.
Now, we know that, perimeter = 50 inches

So, length of sides will be,

184 adults and 201 children swam that day.
(184 × 2) + (201 × 1.50)
368 + 301.50
669.50
Answer:
Step-by-step explanation: •Subtract 2x from both sides of the equation.
-3y = 12 - 2x
•Divide each term by -3y = 12 - 2x by -3.
-3y/-3 = 12/-3 + -2x/-3
•Cancel the common factor of -3.
12/-3 + -2x/-3
•Divide y by 1.
y = 12/-3 + -2x/-3
•Simplify each term.
•Divide 12 by -3.
y = -4 + -2x/-3
•Dividing two negatives values results in a positive value.
y = -4 + 2x/3
Answer:
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