I need help with 10,11,12

Mathematics

2 answers:

Alika [10]3 years ago

8 0

There is a formula u can use to solve all of these problems.
percent formula : is/of = %/100

50 is x% of 300
is = 50
of = 300
% = x
now sub

50/300 = x/100
cross multiply
(300)(x) = (50)(100)
300x = 5000
x = 5000/300
x = 16.67%

use the same formula for the other questions.
35% of 150 is x

is = x
of = 150
% = 35

x/150 = 35/100
cross multiply
(100)(x) = (35)(150)
100x = 5250
x = 5250/100
x = 52.5 <==

x is 200% of 40
is = x
of = 40
% = 200

x/40 = 200/100
cross multiply
(100)(x) = (40)(200)
100x = 8000
x = 8000/100
x = 80

pshichka [43]3 years ago

3 0

10. 50 is roughly around ~16% of 300. (16% is 50.1)

11. 35% of 150 would be 52.5

12. 80 is 200% of 40

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Distance between (-6, -2) and (0,-1)

s344n2d4d5 [400]

Hey there! I'm happy to help!

To find the distance between two points, you square the difference of the x-values and square the difference of the y-values, add them, and then you square root it!

First, we'll add our two x-values.

-6-0= -6

We square it, which means to multiply it by itself.

-6(-6)=36 (If you multiply an even number of negative numbers, your answer is positive. Since we have two negative numbers, we get positive 36)

Now, we do the same with the y-values.

-2-(-1)=-1 (two negatives make it a plus, as in minus minus 1 is plus one.)

We square it.

-1(-1)=1

Now, we add these x and y value differences.

36+1=37

Now, we find the square root using a calculator.

√37≈6.08

Have a wonderful day!

5 0

2 years ago

Pwease help me anyone. thanks :-) :-) :-) :-) :-) :-) :-) :-)!!!!

adell [148]

A)
$x+3$

b)
$x(x+3)=340\\
x^2+3x-340=0$

c)
$x(x+3)=340\\ x^2+3x-340=0\\
\Delta=3^2-4\cdot1\cdot(-340)=9+1360=1369\\\sqrt{\Delta}=37\\
x_1=\dfrac{-3-37}{2}=-20\\
x_2=\dfrac{-3+37}{2}=17$

It's 17.

3 0

3 years ago

A set of data items is normally distributed with a mean of 400 and a standard deviation of 60. Find the data item in this distri

Softa [21]

Answer:

The data item is $X = 580$

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 400 and a standard deviation of 60.

This means that $\mu = 400, \sigma = 60$