1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ddd [48]
3 years ago
15

Are 4vw, 3w2v, and 2wvw like terms? help?

Mathematics
1 answer:
blondinia [14]3 years ago
3 0
No for them to be like terms they would have the same variable for an example 2X and 8X are like terms or 4vw and 10vw are like terms
You might be interested in
10. What is the value of xin the equation below?<br> 4<br> 2<br> +<br> 7<br> 2
Ann [662]
2/x + 1/7 = 4/x

2/x + 4/x = -1/7 move the terms

Transform the expression

-2/x =-1/7 change the signs

2/x = 1/7 cross multiply

Final answer X= 14
3 0
3 years ago
THE GREATEST PRODUCT
Alex17521 [72]

Answer:

<em>7*6543=45801</em>

Step-by-step explanation:

We have the digits 34567 and must arrange them into a product with the largest possible value.

It's clear that we must place the largest digits to the left, so they represent larger numbers to multiply.

Let's try with:

7654*3=22962

765*43=32895

76*543=41268

7*6543=45801

This last combination definitely produces the largest product

Answer: 7*6543=45801

5 0
3 years ago
Please help please and thank you
Katyanochek1 [597]

Step-by-step explanation:

\text{We know:}\\\\\sin(-\alpha)=-\sin\alpha\\\\\sin(\alpha\pm k\cdot360^o)=\sin\alpha\\\\===============================\\\\\sin(360^o-\theta)=\sin\bigg(-(\theta-360^o)\bigg)=-\sin(\theta-360^o)=-\sin\theta

3 0
3 years ago
BRAINLIESTTT ASAP! PLEASE HELP ME :)
yan [13]

Answer:

<em>P=1620</em>

<em>Third option</em>

Step-by-step explanation:

<u>Horizontal Asymptotes</u>

A given function is said to have a horizontal asymptote in y=a, if:  

\displaystyle \lim _{x\rightarrow -\infty }f(x)=a

Or,

\displaystyle \lim _{x\rightarrow +\infty }f(x)=a

For the given function, the population of the species of bird is given by :

\displaystyle p(t)=\frac{1620}{1+1.15e^{-0.042t}}

Where t is the time in years. To find the horizontal asymptote, we should compute both limits to check if they exist.  

\displaystyle \lim _{x\rightarrow +\infty }\frac{1620}{1+1.15e^{-0.042t}}=\frac{1620}{1+0}=1620

When t tends to plus infinity, P tends to 1620 .

The second asymptote is computed by:

\displaystyle \lim _{x\rightarrow -\infty }\frac{1620}{1+1.15e^{-0.042t}}=\frac{1620}{1+\infty}=0

When t tends to minus infinity, P tends to zero. Since the domain of P is t\geq 0, this asymptote is not valid, thus our only asymptote is

\boxed{P=1620}

6 0
3 years ago
Sketch a graph of x + y= -5
olchik [2.2K]

Answer:

Slope:-1

y-intercept:(0,5)

Step-by-step explanation:Hope this helps!!

5 0
3 years ago
Other questions:
  • Hey guys what this answer step-by-step step<br> 2(7x+5)=122
    5·2 answers
  • The graph of y &gt; 1 2 x - 2 is shown. Which set contains only points that satisfy the inequality? A) {(6, 1), (-1, -3), (4, 4)
    10·1 answer
  • A triangle with equal sides and a square have the same perimeters. The length of a side of the triangle is 2x + 2. The length of
    15·1 answer
  • Please help me. thank you.
    9·1 answer
  • The Williams family wants to cover one wall in their living room with 1-foot square mirror tiles. The wall measures 8 feet by 10
    11·1 answer
  • Simplify: 0.9(3÷2.25− 1 8 (1 2 3 + 1 9 ))− 4 7 ÷0.8
    9·1 answer
  • Sharon uses 72 centimeters of ribbon to wrap gifts she uses 24 centimeters of her total ribbon to wrap a big gift she uses the r
    6·2 answers
  • rectangle 2 is a scale drawing of rectangle b and has 25% of its area if rectangle A has side lengths of 4cm and 5cm what are th
    15·2 answers
  • Ms lee is handing out wristbands as students enter the dance. There are 40 black , 20 yellow, 25 orange, and 15 purple wristband
    15·2 answers
  • PLEASE HELP ME!!!! (;´༎ຶٹ༎ຶ`)<br> It needs to be put in slope intercept form
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!