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3 years ago

9

Pat has a fever.His temperature is 99.3F. If the conversation is Celsius is C=5/9(F-32), what is the most accurate measurement o

f Pat’s temperature in degrees Celsius?

1 answer:

Dmitriy789 [7]3 years ago

7 0

Answer:

37.4

Step-by-step explanation:

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25) Wal-Mart is having a sale on packs of pencils. A pack of 24 pencils is on sale for $0.48. I plan to buy 20 packs of pencils.

Bezzdna [24]

Multiply the 20 packs by the 0.48 per pack
Your answer will be $9.60

4 0

2 years ago

Read 2 more answers

A softball has a diameter of 3.82 inches. How many square inches of material is necessary to cover a softball? Use 3.14 for π

lisabon 2012 [21]

Answer:

45.82 square inches

Step-by-step explanation:

Use the formula for the surface area of a sphere, A = 4 $\pi$ r²

If the diameter is 3.82 inches, the radius is 1.91 inches.

Plug in 3.14 as $\pi$ and 1.91 as r, and solve:

A = 4 $\pi$ r²

A = 4(3.14)(1.91²)

A = 45.82

So, approximately 45.82 square inches of material are needed.

6 0

2 years ago

The radius of a circle is changing at the rate of 1/π inches per second. At what rate, in square inches per second, is the circl

MAXImum [283]

Answer:

10 square inches per second.

Step-by-step explanation:

The radius of the circle is given by the equation:

r(t) = (1/π in/s)*t

Where time in seconds.

Remember that the area of a circle of radius R is written as:

A = π*R^2

Then the area of our circle will be:

A(t) = π*( (1/π in/s)*t)^2 = π*(1/π in/s)^2*(t)^2

Now we want to find the rate of change (the first derivation of the area) when the radius is equal to 5 inches.

Then the first thing we need to do is find the value of t such that the radius is equal to 5 inches.

r(t) = 5 in = (1/ in/s)*t

5in*(π s/in) = t

5*π s = t

So the radius will be equal to 5 inches after 5*π seconds, let's remember that.

Now let's find the first derivate of A(t)

dA(t)/dt = A'(t) = 2*(π*(1/π in/s)^2*t = (2*π*t)*(1/π in/s)^2

Now we need to evaluate this in the time such that the radius is equal to 5 inches, we will get:

A'(5*π s) = (2*π*5*π s)*((1/π in/s)^2

= (10*π^2 s)*(1/π^2 in^2/s^2) = 10 in^2/s

The rate of change is 10 square inches per second.

4 0

2 years ago

Which graph is a function of x

timurjin [86]

Answer:

the answer is the 2nd one the one with the v shape

Step-by-step explanation:

if you do the vertical line test which is just drawing a vertical line through the line and it intersect the line twice than it is NOT functional

(i think i do not know D:)

5 0

2 years ago

From the top of a vertical cliff 50 m high, the angle of depression of an object that is level with the base of the cliff is 70°

Svetlanka [38]

Answer:

The distance of the object from the base of cliff is 18.24 meters

Step-by-step explanation:

Given as :

The height of the vertical cliff = h = 50 meters

The distance of the object from the base of cliff = x meters

Let The angle of depression of object that level with cliff base = Ф = 70°

<u>Now, from figure</u>

Tan angle = $\dfrac{\textrm perpendicular}{\textrm base}$

I.e TanФ = $\dfrac{\textrm AB}{\textrm OA}$

Or, TanФ = $\dfrac{\textrm h}{\textrm x}$

Or, Tan 70° = $\dfrac{\textrm 50 meters}{\textrm x meters}$

Or, 2.74 = $\dfrac{\textrm 50}{\textrm x}$

∴ x = $\dfrac{\textrm 50}{\textrm 2.74}$

I,e x = 18.24 meters

So, The distance of the object from the base of cliff = x = 18.24 meters

Hence,The distance of the object from the base of cliff is 18.24 meters Answer

5 0

3 years ago