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What is the equation of the line parallel to y=-5x-9 and contains the point (-3, -3)?
First of all, parallel lines have the exact same slope.
So we know the slope of the line:- -5.
(enter -5, It's the number that belongs in the green box)
How about the y-intercept?
Well, since we're given the slope and a point that the line intersects, we can write the line's equation in point-slope form:-
y-y1=m(x-x1)
y-(-3)=-5(x-(-3)
y+3=-5(x+3)
y+3=-5x-15
y=-5x-18
<h3>Good luck.</h3>
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Answer:
C
Step-by-step explanation:
substitute f(x) into g(x)
g(x) = f(x) + 9 = -3x - 5 + 9 = - 3x + 4
To find the y-intercept solve g(0)
g(0) = 0 + 4 = 4 ← y- intercept → (0, 4 ) → C
Answer:
-6.13406 and 61.13406
Step-by-step explanation:
x + y = 55
x × y = -375
y = 55 - x
x × (55 - x) = -375
55x -x² = -375
x² - 55x - 375 = 0
solution of a quadratic equation :
x = (-b ± sqrt(b² - 4ac))/(2a)
a=1
b=-55
c=-375
x = (55 ± sqrt(55² + 4×375))/2 = (55 ± sqrt(4525))/2 =
= (55 ± sqrt(25 × 181))/2 = (5×11 ± 5×sqrt(181))/2 =
= 5/2 × (11 ± sqrt(181)) =
= 61.13406... or -6.13406...
y = 55 - 5/2×(11 ± sqrt(181)) = 55/2 ± 5/2×sqrt(181) =
= -6.13406... or 61.13406...
Answer:
c
Step-by-step explanation: