Answer:
use pressure =Force /area
Step-by-step explanation:
12000N/1.08
Substitute <em>x</em> = 3 - 2 cos(<em>θ</em>) and d<em>x</em> = 2 sin(<em>θ</em>) d<em>θ</em> (where "sin" = "sen"). So we have
∫ sin(<em>θ</em>) / (3 - 2 cos(<em>θ</em>)) d<em>θ</em> = 1/2 ∫ 1/<em>x</em> d<em>x</em>
= 1/2 ln|<em>x</em>| + <em>C</em>
= 1/2 ln(3 - 2 cos(<em>θ</em>)) + <em>C</em>
(We can remove the absolute value because -1 ≤ cos(<em>θ</em>) ≤ 1, so 1 ≤ 3 - 2 cos(<em>θ</em>) ≤ 5, and |<em>x</em>| = <em>x</em> when <em>x</em> ≥ 0.)
Multiply the second question by -1 to cancel out the y’s. then add them. 11x=-11
x=-1
substitute that back into one of the equations
-3(-1)+y=-5
3+y=-5
y=-8
Answer:
They are called vertical angles but are also known as "Vertically Opposite Angles"
Step-by-step explanation:
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Answer:
Step-by-step explanation:
Quadratic formula: 
Hope this helps and God bless!
