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3 years ago

2x+9=25 need reason for its statement

1 answer:

wel3 years ago

4 0

Look at 2%2Ax%2B9=highlight_red%28+25+%29.
Moved these terms to the left highlight_green%28+-25+%29
It becomes 2%2Ax%2B9-highlight_green%28+25+%29=0.
Look at 2%2Ax%2Bhighlight_red%28+9+%29-highlight_red%28+25+%29=0.
Added fractions or integers together
It becomes 2%2Ax%2Bhighlight_green%28+-16+%29=0.
Look at 2%2Ax%2Bhighlight_red%28+-16+%29=0.
Removed extra sign in front of -16
It becomes 2%2Ax-highlight_green%28+16+%29=0.
Look at highlight_red%28+2%2Ax-16+%29=0.
Solved linear equation highlight_red%28+2%2Ax-16=0+%29 equivalent to 2*x-16 =0
It becomes highlight_green%28+0+%29=0.
Result: 0=0
This is an equation! Solutions: x=8.

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Which set of ordered pairs does not represent a function?

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Answer: The last

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1 year ago

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(x^3)^9 = <br> A: x^12 <br> B: x^27 <br> C: x^3 <br> D: x^6

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$(x^3)^9=x^{27}$

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3 years ago

Plz help with these first one gets brainliest

vlabodo [156]

Answer:

A=(1,6) B=(1,6)

Step-by-step explanation:

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Answer:

sample (a

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3 years ago

Please help ASAP!

Kruka [31]

First, recall that

$\sin(-\theta)=-\sin\theta$

So if $\sin(-\theta)=\dfrac15$ , then $\sin\theta=-\dfrac15$ .

Second,

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}$

We know that $\tan\theta>0$ and $\sin\theta$ , which means we should also have $\cos\theta$ .

Third,

$\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\pm\sqrt{1-\sin^2\theta}$

but as we've already shown, we need to have $\cos\theta$ , so we pick the negative root.

Finally,

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}\iff\dfrac6{\sqrt{12}}=\dfrac{-\frac15}{\cos\theta}\implies\cos\theta=-\dfrac1{5\sqrt3}$

Unfortunately, none of the given answers match, so perhaps I've misunderstood one of the given conditions... In any case, this answer should tell you everything you need to know to find the right solution from the given options.

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3 years ago