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3 years ago

What is 2 1/2 + 1 1/8?

Mathematics

2 answers:

STALIN [3.7K]3 years ago

4 0

Answer:

3 5/8

Step-by-step explanation:

2 1/2 + 1 1/8

Convert to improper fractions.

5/2 + 9/8

Make the denominators equal.

40/16 + 18/16

Add the fractions.

58/16

Simplify.

29/8 ⇒ 3 5/8

miskamm [114]3 years ago

3 0

Answer:

3 5/8

Step-by-step explanation:

In order to solve this problem, the fractions need to have a common denominator.

1/2= 4/8

Now, our problem is 2 4/8 + 1 1/8.

Add

3 5/8

Let me know if you need further explanation!

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⁠ 23 56 − ⁠ 1 8 Write the answer in simplest form.

lidiya [134]

Answer:

Convert to a simplified fraction.

1/169

Step-by-step explanation:

i think this is right im not sure IM SO SORRY IF THIS IS THE WRONG ANSWER

4 0

3 years ago

Identify all the sets to which the number 3.1214122144 belongs

marishachu [46]

The set of numbers that 3.1214122144 belongs to is called the Irrational numbers. We know this because this number it is not an integer, since it has a fractional part and also is not a whole number. Rational numbers can be decimals but they are terminating decimals. This number is irrational because is a non ending decimal number.

4 0

4 years ago

There are 18 tables at a party each table can seat six people complete the equation to show which operation to use and the total

galina1969 [7]

I can't complete the equation or the sentence because they have not been provided. However, I can write you an equation to model this situation.

Answer:

18x6=108

Step-by-step explanation:

If each table seats 6 people, there are 18 tables, and we are trying to find the total number of seated persons, it can be modeled as such:

tables x capacity of each table=total number of seated persons

plug in:

18x6=108

8 0

4 years ago

Write the first three terms of the series for which tn = 2(n+3). Find the number of terms of the series required to make the sum

ira [324]

Answer:

The first three terms of the series are 8, 10 and 12. The number of terms is 12 to make the sum 228.

Step-by-step explanation:

The series is defined as

$t_n=2(n+3)$

Put n=1.

$t_1=2(1+3)=2\times 4=8$

Put n=2.

$t_2=2(2+3)=2\times 5=10$

Put n=3.

$t_3=2(3+3)=2\times 6=12$

The first three terms of the series are 8, 10 and 12.

It is an arithmetic series. The first terms is 8 and the common difference is

$d=a_2-a_1=10-8=2$

The sum of n terms of an arithmetic series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$288=\frac{n}{2}[2(8)+(n-1)2]$

$288=\frac{2n}{2}[8+n-1]$

$288=n[n+7]$

$0=n^2+7n-288$

$0=n^2+19n-12n-288$

$0=n(n+19)-12(n+19)$

$0=(n+19)(n-12)$

Equate each factor equal to zero.

$n=-19,12$

The number of terms can not be negative, therefore the value of n must be 12.

6 0

3 years ago

Write the point-slope form of the equation of the line that passes through the points (-8, 2) and (1, -4).

Kruka [31]

So point-slope form is (y-y1) = m(x-x1). So first find m. m = (y2-y1) / (x2-x1) So for your problem m = (-4-2) / (1--8) = -6/9 = -2/3. Then plug the slope and a point into the point-slope equation so you can either get: y-2 = (-2/3)*(x+8) or y+4 = (-2/3)*(x-1). Both are valid.

Hope this helps!

3 0

4 years ago