1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MariettaO [177]
3 years ago
12

What is the average of the integers from 25-41

Mathematics
2 answers:
Licemer1 [7]3 years ago
7 0

The average of 25 and 41 is (1/2)(25+41) = (1/2)(66) = 33 .

Similarly ...
--The average of 26 and 40 is 33.
-- The average of 27 and 39 is 33.
-- The average of 28 and 38 is 33.
-- The average of 29 and 37 is 33.
-- The average of 30 and 36 is 33.
-- The average of 31 and 35 is 33.
-- The average of 32 and 34 is 33.
-- That leaves only 33.

So the average of all of those 17 integers is 33 .

Mashcka [7]3 years ago
4 0
The answer is 33 for your question

You might be interested in
Which expression is equivalent to (x Superscript 27 Baseline y) Superscript one-third?.
marin [14]

To solve the problem we must know the basic exponential properties.

<h3>What are the basic exponent properties?</h3>

{a^m} \cdot {a^n} = a^{(m+n)}

\dfrac{a^m}{a^n} = a^{(m-n)}

\sqrt[m]{a^n} = a^{\frac{n}{m}}

(a^m)^n = a^{m\times n}

(m\times n)^a = m^a\times n^a

The expression can be written as x^9\sqrt[3]{y}.

Given to us

  • (x^{27}y)^\frac{1}{3}

(x^{27}y)^\frac{1}{3}

Using the exponential property(m\times n)^a = m^a\times n^a,

=(x^{27}y)^\frac{1}{3}\\\\=x^{\frac{27}{3}}\times y^\frac{1}{3}\\\\=x^9\times y^\frac{1}{3}

Using the exponential property \sqrt[m]{a^n} = a^{\frac{n}{m}},

=x^9\times y^\frac{1}{3}\\\\=x^9\times \sqrt[3]{y}\\\\=x^9 \sqrt[3]{y}

Hence, the expression can be written as x^9\sqrt[3]{y}.

Learn more about Exponent properties:

brainly.com/question/1807508

5 0
2 years ago
Read 2 more answers
(x +y)^5<br> Complete the polynomial operation
Vesna [10]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the polynomial

\left(x+y\right)^5

\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i

a=x,\:\:b=y

=\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i

so expanding summation

=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5

solving

\frac{5!}{0!\left(5-0\right)!}x^5y^0

=1\cdot \frac{5!}{0!\left(5-0\right)!}x^5

=1\cdot \:1\cdot \:x^5

=x^5

also solving

=\frac{5!}{1!\left(5-1\right)!}x^4y

=\frac{5}{1!}x^4y

=\frac{5}{1!}x^4y

=\frac{5x^4y}{1}

=\frac{5x^4y}{1}

=5x^4y

similarly, the result of the remaining terms can be solved such as

\frac{5!}{2!\left(5-2\right)!}x^3y^2=10x^3y^2

\frac{5!}{3!\left(5-3\right)!}x^2y^3=10x^2y^3

\frac{5!}{4!\left(5-4\right)!}x^1y^4=5xy^4

\frac{5!}{5!\left(5-5\right)!}x^0y^5=y^5

so substituting all the solved results in the expression

=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5

=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5

Therefore,

\left(x\:+y\right)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5

6 0
3 years ago
Can someone please help
Sonja [21]

Answer:

i have no idea lol make it more clearer

6 0
3 years ago
In mathematics, the distance between one point (a) and another point (b), each with coordinates (x,y), can be computed by taking
anygoal [31]
The formula to find the distance between points P_{1} and x_{2} is given as \sqrt{ ( y_{1}- y_{2})  ^{2}+ ( x_{1}- x_{2})  ^{2}  }, where

y_{1}- y_{2} is the vertical distance between two points on the y-axis
x_{1} - x_{2} is the horizontal distance between two points on the x-axis

8 0
3 years ago
I really need the help.....
prisoha [69]

Answer:

Similar - Top center, bottom left

Not similar, different shape - Top left, bottom right

Not similar, different ratio of side lengths - Top right, bottom center

Step-by-step explanation:

We can see automatically that the top left and bottom right are not similar because they are a triangle and a trapezoid, not a rectangle.

Top right is not similar because of its different ratio of sides. The ratio for the sides of the original rectangle is 3:7, while the ratio of the top right is 2:3.5 .

Bottom center is not similar because of its different ratio of sides as well, as its ratio is 6:12

6 0
3 years ago
Other questions:
  • A square pyramid with a = 20 mm and b = 96 mm is shown. What is the length of side c? *Hint: you must divide the "b" by two to f
    13·2 answers
  • Use the x-intercept method to find all real solutions of the equation. x^3-10x^2+29x+-20=0
    8·2 answers
  • I need help on question #20 please!!!! Also show work!!! And tell me why the answer to the problem is correct. THANK YOU!!!
    10·1 answer
  • I don't understand this plz help
    5·1 answer
  • 5ry - c = q<br> solve for r
    11·1 answer
  • 3x + 4y = 27 5x - 3y = 16
    11·1 answer
  • Someone please help me asap !!!!
    7·1 answer
  • Samantha drove her car with a full tank of gas 268 miles to her friends town for an average of 22.68 miles/gallons and then refi
    12·1 answer
  • Which of the following is equivalent to 5 • (7 • 4)?
    6·1 answer
  • Help i need it its math
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!