2/3 in front x10
3/10 behind x3
20/30 In front
9/30 behind
20/30+9/30= 29/30
30 people are in the queue
Let there be a advanced tickets and s same day tickets, Then:-
a + s = 40
20a + 30s = 950............................(1)
Multiply first equation by -30
-30a - 30x = -1200 .....................(2)
Adding equations (1) and (2):-
-10a = - 250
a = -250/-10 = 25
So s = 40 - 25 = 15
Answer:- advanced tickets cost $25 and same day cost $15.
Assuming that this is a linear relationship you must find the rate of change...$23.81-$20.70= $3.11. 3.11 is how much it changed that year. What that also gives you is how much you bought the post for at 0 years by subtracting $20.70 and the $3.11 = the price of the poster. This gives us the equation y=3.11(x)+17.59
Where Y is the value and X is the amount of years.
3 bc if she all ready walks 2 and she runs 3 times as far as dante then she will walk 3 miles if Dante runs 1<span />