All categories

3 years ago

5ry - c = q solve for r

Mathematics

1 answer:

Tems11 [23]3 years ago

4 0

Answer:

r = (q + c)/5y

Step-by-step explanation:

in order to solve this expression thereby expressing r in terms of y,c and q.

5ry - c = q

from the above expression

5ry = q + c

divide both sides by 5y

5ry/5y = q + c/5y

r = (q + c)/5y

You might be interested in

Will mark brain list if answered correct) On this number line, zero represents sea level. Plot the following points based on the

Flauer [41]

Answer:

The points would be:

1.5

4.5

-2

-4

-2.5

-3.5

Step-by-step explanation:

8 0

3 years ago

Answer for <br> 5.3 (2×+5)=

den301095 [7]

Answer:

10.6

26.5

Step-by-step explanation:

7 0

3 years ago

Describe how 30,434 and 43,403 are alike and how they ate different

pantera1 [17]

The second one is greater because 4 is bigger than 3.

4 0

4 years ago

Read 2 more answers

What is the expression for "the sum of 8 times a number and two"?

LiRa [457]

Answer:

8 N + 2

Step-by-step explanation:

==> 8 N + 2

-----------_________-------------

8 0

2 years ago

each course in college X is worth either two or three credits the members of the men’s swim team are taking a total of 47 course

omeli [17]

36 two credit courses and 11 three credit courses has been taken.

<u>SOLUTION: </u>

Given, each course in college X is worth either two or three credits. The members of the men’s swim team are taking a total of 47 courses that are worth a total of 105 credits .

We have to number of two credit courses and three credit courses are being taken .

Now, let the number of 2 credits courses be n, then number of 3 credits courses will be $47-n$ .

And, according to the given information, Total credits = 105

$\begin{array}{l}{\rightarrow \text { Credits for two credit courses }+\text { credits from three credits courses }=105} \\\\ {\rightarrow 2 \times \text { number of two credit courses }+3 \times \text { number of three lcredit courses }=105} \\\\ {\rightarrow 2 \times n+3 \times(47-n)=105} \\\\ {\rightarrow 2 n+141-3 n=105} \\\\ {\rightarrow 3 n-2 n=141-105} \\\\ {\rightarrow n=36}\end{array}$

So, two credits courses count is 36, the three credit courses count is $47-36 = 11$

8 0

3 years ago